优优班--学霸训练营 > 题目详情
  • 下面均是正丁烷与氧气反应的热化学方程式\(\rm{(25℃,101kPa)}\):
    \(\rm{①C_{4}H_{10}(g)+ \dfrac {13}{2}O_{2}(g)═4CO_{2}(g)+5H_{2}O(l)\triangle H=-2}\) \(\rm{878kJ⋅mol^{-1}}\)
    \(\rm{②C_{4}H_{10}(g)+ \dfrac {13}{2}O_{2}(g)═4CO_{2}(g)+5H_{2}O(g)\triangle H=-2}\) \(\rm{658kJ⋅mol^{-1}}\)
    \(\rm{③C_{4}H_{10}(g)+ \dfrac {9}{2}O_{2}(g)═4CO(g)+5H_{2}O(l)\triangle H=-1}\) \(\rm{746kJ⋅mol^{-1}}\)
    \(\rm{④C_{4}H_{10}(g)+ \dfrac {9}{2}O_{2}(g)═4CO(g)+5H_{2}O(g)\triangle H=-1}\) \(\rm{526kJ⋅mol^{-1}}\)
    由此判断,正丁烷的燃烧热是\(\rm{(}\)  \(\rm{)}\)
    【考点】燃烧热,热化学方程式
    【分析】请登陆后查看
    【解答】请登陆后查看
    难度:较易
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