已知\(S_{n}\)是等差数列\(\{a_{n}\}\)的前\(n\)项和，则\(2(a_{1}+a_{3}+a_{5})+3(a_{8}+a_{10})=36\)，则\(S

已知\(S_{n}\)是等差数列\(\{a_{n}\}\)的前\(n\)项和，则\(2(a_{1}+a_{3}+a_{5})+3(a_{8}+a_{10})=36\)，则\(S_{11}=(\)　　\()\)

A．\(66\)

B．\(55\)

C．\(44\)

D．\(33\)

【考点】等差数列的求和

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难度：较易

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