已知等差数列\(\{a_{n}\}\)满足：\(a_{3}=7\)，\(a_{5}+a_{7}=26\)，\(\{a_{n}\}\)的前\(n\)项和为\(S_{n}\)．
\((\)Ⅰ\()\)求\(a_{n}\)及\(S_{n}\)；
\((\)Ⅱ\()\)令\(b_{n}= \dfrac {1}{a_{n}^{2}-1}(n∈N^{*})\)，求数列\(\{b_{n}\}\)的前\(n\)项和\(T_{n}\)．