已知函数\(f(x)(x∈R)\)满足\(f(-x)=2-f(x)\)，若函数\(y= \dfrac {x+1}{x}\)与\(y=f(x)\)图象的交点为\((x_{1},y_{1})\)，\((x_{2},y_{2})\)，\(…\)，\((x_{m},y_{m})\)，则\( \sum\limits_{i=1}^{m}(x_{i}+y_{i})=(\)　　\()\)