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  • 已知数列\(\{a_{n}\}{中},a_{1}= \dfrac {1}{2},{点}(n,2a_{n+1}-a_{n})(n∈N^{*}){在直线}y=x{上}\),
    \((\)Ⅰ\()\)计算\(a_{2}\),\(a_{3}\),\(a_{4}\)的值;
    \((\)Ⅱ\()\)令\(b_{n}=a_{n+1}-a_{n}-1\),求证:数列\(\{b_{n}\}\)是等比数列;
    \((\)Ⅲ\()\)设\(S_{n}\)、\(T_{n}\)分别为数列\(\{a_{n}\}\)、\(\{b_{n}\}\)的前\(n\)项和,是否存在实数\(λ\),使得数列\(\{ \dfrac {S_{n}+λT_{n}}{n}\}\)为等差数列?若存在,试求出\(λ\)的值;若不存在,请说明理由.
    【考点】等比数列的判定与证明,数列的函数特征,等差数列的通项公式,等差数列的求和
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    【解答】请登陆后查看
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