如图,双曲线\(y=\dfrac{2}{x}(x > 0)\)经过四边形\(OABC\)的顶点\(A\)、\(C\),\(∠ABC=90^{\circ}\),\(OC\)平分\(OA\)与\(x\)轴正半轴的夹角,\(AB/\!/x\)轴,将\(\triangle ABC\)沿\(AC\)翻折后得到\(\triangle AB′C\),\(B′\)点落在\(OA\)上,则四边形\(OABC\)的面积是\((\) \()\)
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