已知:如图,在菱形\(ABCD\)中,\(E\),\(F\)分别是\(CB\),\(CD\)上的点,且\(BE=DF\)
\((1)\)求证:\(AE=AF\);
\((2)\)若\(∠B=60^{\circ}\),\(E\),\(F\)分别为\(BC\),\(CD\)的中点,求证:\(\triangle AEF\)为等边三角形.
进入组卷