已知一组数据\({x}_{1},{x}_{2},{x}_{3},{x}_{4},{x}_{5} \)的平均数是\(2 \),方差是\(\dfrac{1}{3} \),那么另一组数据\(3{x}_{1}−2,3{x}_{2}−2,3{x}_{3}−2,3{x}_{4}−2,3{x}_{5}−2 \)的平均数,方差是( )
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