如图,梯形\(ABCD\)中,\(AD= BC\),\(AB\parallel CD\),\(AC\bot BD\),平面\(BDFE\bot \)平面\(ABCD\),\(EF\parallel BD\),\(BE\bot BD\)
\((1)\)求证:平面\(AFC\bot \)平面\(BDFE;\)
\((2)\)若\(AB=2CD2\sqrt{2}\) ,\(BE = EF =2\),求\(BF\)与平面\(DFC\)所成角的正弦值.
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