己知曲线\(C_{1}︰y_{2}=tx(y > 0,t > 0)\)在点\(M(\dfrac{4}{t},2)\)处的切线与曲线\(C_{2}︰y=e^{x+1}-1\)也相切,则\(t\ln \dfrac{4{{e}^{2}}}{t}\)的值为\((\) \()\)
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