等比数列\(\{a_{n}\}\)中,已知\(a_{1}=2\),\(a_{4}=16\).
\((1)\)求数列\(\{a_{n}\}\)的通项公式;
\((2)\)若\(a_{3}\),\(a_{5}\)分别为等差数列\(\{b_{n}\}\)第\(3\)项和第\(5\)项,求数列\(\{b_{n}\}\)的通项公式及前\(n\)项和\(S_{n}\).
进入组卷