己知数列\(\{a_{n}\}\),\(a_{1}=1\),\(a_{n+1} > a_{n}\),\((a_{n}+a_{n+1}-1)^{2}=4a_{n}a_{n+1}(n∈N^{*}).\)
\((1)\)求数列\(\{a_{n}\}\)的通项公式;
\((2)\)记\({{b}_{n}}=\dfrac{1}{\sqrt[4]{{{a}_{n}}}}\),\(T_{n}=b_{1}+b_{2}+…+b_{n}\),估算\(T_{2017}\)的整数部分.
\((\)参考数据:\(1.41 < \sqrt{2} < 1.42\),\(44.92 < \sqrt{2018} < 45)\)