直线\(\begin{cases} & x=1+2t \\ & y=2+t \\ \end{cases}(\)\(t\)为参数\()\)被圆\(x\)\({\,\!}^{2}+\)\(y\)\({\,\!}^{2}=9\)截得的弦长等于 \((\)\()\)--优优班--学霸训练营

直线\(\begin{cases} & x=1+2t \\ & y=2+t \\ \end{cases}(\)\(t\)为参数\()\)被圆\(x\)\({\,\!}^{2}+\)\(y\)\({\,\!}^{2}=9\)截得的弦长等于 \((\) \()\)

A．\(\dfrac{12}{5}\)

B．\(\dfrac{12}{5}\sqrt{2}\)

C．\(\dfrac{9}{5}\sqrt{2}\)

D．\(\dfrac{12}{5}\sqrt{5}\)

【考点】圆的弦有关的综合问题,直线的参数方程

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【解答】请登陆后查看

难度：易

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