已知各项都是正数的数列\(\{a_{n}\}\)满足\(a_{1}=1\),\({{a}_{n+1}}=\dfrac{{{a}_{n}}+{1}}{{12}{{a}_{n}}}(n\in {{N}^{{*}}})\).
\((1)\)用数学归纳法证明:\(a_{2n+1} < a_{2n-1}\);
\((2)\)证明:\(\dfrac{1}{6}\leqslant {{a}_{n}}\leqslant 1\).
进入组卷