共50条信息
如下是小明对问题作出的判断,
\((1){{a}^{0}}=1(√)\)
\((2)\sqrt{64}=\pm 8(×)\)
\((3)\)单项式\(-\dfrac{2{{x}^{2}}y}{5}\)的系数是\(-2(×)\)
\((4)\)倒数是它本身的数是\(\pm 1(√)\)
\((5)\)把\(-0.00041\)写成科学计数法是\(-4.1\times {{10}^{-4}}(√)\);
若每小题\(20\)分,则他的得分应是
\(a\)是不为\(1\)的有理数,我们把\(\dfrac{1}{1-a}\)称为\(a\)的差倒数\(.\)如:\(3\)的差倒数是\(\dfrac{1}{1-3}=-\dfrac{1}{2}\),\(-1\)的差倒数是\(\dfrac{1}{1-(-1)}=\dfrac{1}{2}.\)已知\(a_{1}=2\),\(a_{2}\)是\(a_{1}\)的差倒数,\(a_{3}\)是\(a_{2}\)的差倒数,\(a_{4}\)是\(a_{3}\)的差倒数,\(…\),依此类推,则\(a_{15}=\)____________.
进入组卷