不管化学过程是一步完成或分为数步完成，这个过程的热效应是相同的已知

\(\rm{H_{2}O(g)=H_{2}O(l)}\)；　　　　　　　　　　　　\(\rm{\triangle H_{1}=Q_{1}kJ·molˉ^{1}}\)

        \(\rm{C_{2}H_{5}OH(g)=C_{2}H_{5}OH(l)}\)；　　　　　　　　　\(\rm{\triangle H_{2}=Q_{2} kJ·molˉ^{1}}\)

\(\rm{C_{2}H_{5}OH(g)+3O_{2}(g)=2CO_{2}(g)+3H_{2}O(g)}\)；　  \(\rm{\triangle H_{3}=Q_{3}kJ·molˉ^{1}}\)

若使\(\rm{23 g}\)酒精液体完全燃烧，最后恢复到室温，则放出的热量为      

已知：\(\rm{H_{2}O(g)═H_{2}O(l)\triangle H_{1}=-Q_{1}kJ⋅mol-1(Q_{1} > 0)}\)

已知：\(\rm{①F{e}_{2}{O}_{3}(s)+3CO(g)=2Fe(s)+3C{O}_{2}(g) }\) \(\rm{\Delta H=-25kJ\cdot mo{{l}^{-1}}}\)；\(\rm{②3F{e}_{2}{O}_{3}(s)+CO(g)=2F{e}_{3}{O}_{4}(s)+C{O}_{2}(g) }\) \(\rm{\Delta H=-47kJ\cdot mo{{l}^{-1}}}\)。下列关于\(\rm{Fe_{3}O_{4}(s)}\)被\(\rm{CO}\)还原成\(\rm{Fe(s)}\)和\(\rm{CO_{2}}\)的热化学方程式的书写中正确的是(    )

已知：\(\rm{C(s){+}\dfrac{1}{2}O_{2}(g){═}{CO}(g){\triangle }H_{1}{=-}110{.}5{kJ}{/}{mol}{CO}(g){+}\dfrac{1}{2}O_{2}(g){═}CO_{2}(g){\triangle }H_{2}{=-}283{.}0{kJ}{/}{mol}}\)则反应\(\rm{C(s){+}O_{2}(g){═}CO_{2}(g)}\)的反应热为\(\rm{({  })}\)

已知反应：\(\rm{{①}2H_{2}O(g){=}2H_{2}(g){+}O_{2}(g){\triangle }H_{1}{②}Cl_{2}(g){+}H_{2}(g){=}2{HCl}{\triangle }H_{2}{③}2Cl_{2}(g){+}2H_{2}O(g){=}4{HCl}(g){+}O_{2}(g){\triangle }H_{3}}\)则\(\rm{{\triangle }H_{1}}\)、\(\rm{{\triangle }H_{2}}\)、\(\rm{{\triangle }H_{3}}\)间的关系正确的是\(\rm{({  })}\)

\(\rm{2008}\)年\(\rm{9}\)月我国“神七”发射升空，中国航天员实现首次太空行走运载火箭的原料用肼\(\rm{\left({N}_{2}{H}_{4}\right) }\)作为发动机的燃料，\(\rm{N{O}_{2} }\)为氧化剂，反应生成氮气和水蒸气已知：\(\rm{{N}_{2}\left(g\right)+2{O}_{2}\left(g\right)=2N{O}_{2}\left(g\right);∆H=+67.7KJ/mol }\) \(\rm{{N}_{2}{H}_{4}\left(g\right)+{O}_{2}\left(g\right)={N}_{2}\left(g\right)+2{H}_{2}O\left(g\right);∆-534KJ/mol }\) 下列判断正确的是

已知：\(\rm{H_{2}O(l)=H_{2}O(g)}\)  \(\rm{ΔH=+Q_{1} kJ·mol^{-1}}\)

\(\rm{2H_{2}O(g)=2H_{2}(g)+O_{2}(g)}\)  \(\rm{ΔH=+Q_{2} kJ·mol^{-1}}\)

\(\rm{CH_{4}(g)+2O_{2}(g)=CO_{2}(g)+2H_{2}O(l)}\)  \(\rm{ΔH=-Q_{3} kJ·mol^{-1}}\)

则\(\rm{H_{2}}\)和\(\rm{CH_{4}}\)的燃烧热的比值为

已知胆矾溶于水时溶液温度降低。胆矾分解的热化学方程式为

\(\rm{CuSO_{4}·5H_{2}O(s)=CuSO_{4}(s)+5H_{2}O(l) ΔH=+Q_{1} mol·L^{-1}}\)。室温下，若将\(\rm{1 mol}\)无水硫酸铜溶解为溶液时放热\(\rm{Q_{2} kJ}\)，则\(\rm{Q_{1}}\)与\(\rm{Q_{2}}\)的关系为\(\rm{(}\)   \(\rm{)}\)