知识点挑题 - 高中化学 - 优优班--学霸训练营

\(\rm{H_{2}C_{2}O_{4}}\)为二元弱酸，\(\rm{K_{a1}(H_{2}C_{2}O_{4})=5.4×10^{-2}}\)，\(\rm{K_{a2}(H_{2}C_{2}O_{4})=5.4×10^{-5}}\)，设\(\rm{H_{2}C_{2}O_{4}}\)溶液中\(\rm{c(}\)总\(\rm{)=c(H_{2}C_{2}O_{4})+c(HC_{2}O_{4}^{-})+c(C_{2}O_{4}^{2-})}\)。室温下用\(\rm{NaOH}\)溶液滴定\(\rm{25.00 mL 0.1000mol⋅L^{-1}}\) \(\rm{H_{2}C_{2}O_{4}}\)溶液至终点。滴定过程得到的下列溶液中微粒的物质的量浓度关系一定正确的是\(\rm{(}\)　　\(\rm{)}\)

A．\(\rm{0.1000mol⋅L^{-1}H_{2}C_{2}O_{4}}\)溶液：\(\rm{c(H^{+})=0.1000mol⋅L^{-1}+c(C_{2}O_{4}^{2-})+c(OH^{-})-c(H_{2}C_{2}O_{4})}\)

B．\(\rm{c(Na^{+})=c(}\)总\(\rm{)}\)的溶液：\(\rm{c(Na^{+}) > c(H_{2}C_{2}O_{4}) > c(C_{2}O_{4}^{2-}) > c(H^{+})}\)

C．\(\rm{pH=7}\)的溶液：\(\rm{c(Na^{+})=0.1000mol⋅L^{-1}+c(C_{2}O_{4}^{2-})-c(H_{2}C_{2}O_{4})}\)

D．\(\rm{c(Na^{+})=2c(}\)总\(\rm{)}\)的溶液：\(\rm{c(OH^{-})-c(H^{+})=2c(H_{2}C_{2}O_{4})+c(C_{2}O_{4}^{2-})}\)

难度：较易

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2．

常温下，\(\rm{K_{a}(HCOOH)=1.77×10^{-4}}\)，\(\rm{K_{a}}\) \(\rm{(CH_{3}COOH)=1.75×10^{-5}}\)，\(\rm{K_{b}}\) \(\rm{(NH_{3}⋅H_{2}O)=1.76×10^{-5}}\)，下列说法正确的是\(\rm{(}\)　　\(\rm{)}\)

A．浓度均为\(\rm{0.1mol⋅L^{-1}}\)的 \(\rm{HCOONa}\)和\(\rm{NH_{4}Cl}\) 溶液中阳离子的物质的量浓度之和：前者大于后者

B．用相同浓度的\(\rm{NaOH}\)溶液分别滴定等体积\(\rm{pH}\)均为\(\rm{3}\)的\(\rm{HCOOH}\)和\(\rm{CH_{3}COOH}\)溶液至终点，消耗\(\rm{NaOH}\)溶液的体积相等

C．\(\rm{0.2}\) \(\rm{mol⋅L^{-1}}\) \(\rm{HCOOH}\) 与 \(\rm{0.1}\) \(\rm{mol⋅L^{-1}}\) \(\rm{NaOH}\) 等体积混合后的溶液中：\(\rm{c(HCOO^{-})+c(OH^{-})=c(HCOOH)+c(H^{+})}\)

D．\(\rm{0.2}\) \(\rm{mol⋅L^{-1}}\) \(\rm{CH_{3}COONa}\) 与 \(\rm{0.1}\) \(\rm{mol⋅L^{-1}}\)盐酸等体积混合后的溶液中\(\rm{(pH < 7)}\)：\(\rm{c(CH_{3}COO^{-}) > c(Cl^{-}) > c(CH_{3}COOH) > c(H^{+})}\)

难度：难

解析收藏试题篮

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