共50条信息
\((1)\)计算:\({( \dfrac{1}{3})}^{−1}−{(π−3)}^{0}−4\sin {60}^{{}^{∘}}+ \sqrt{12} \).
\((2)\)解方程:\( \dfrac{2x+2}{x}− \dfrac{x+2}{x−2}= \dfrac{{x}^{2}−2}{{x}^{2}−2x} \).
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