阅读材料:求\(1+2+2^{2}+2^{3}+2^{4}+…+2^{17}\)的值.
解:设\(S=1+2+2^{2}+2^{3}+2^{4}+…+2^{2016}+2^{2017}\),
等式两边同时乘\(2\)得:
\(2S=2++2\)\({\,\!}^{2}\)
\(+2\)\({\,\!}^{3}\)
\(+2\)\({\,\!}^{4}\)
\(+2\)\({\,\!}^{5}\)
\(…+2\)\({\,\!}^{2017}\)
\(+2\)\({\,\!}^{2018}\)
\({\,\!}^{\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;}\)将下式减去上式得:\(2S-S=2\)\({\,\!}^{2018}\)\(-1\)
\(S=2^{2018}-1\)
即\(1+2+2^{2}+2^{3}+2^{4}+…+2^{2017}=2^{2018}-1\)
请你仿照此法计算:
\((1)1+2+2^{2}+2^{3}+2^{4}+…+2^{10}\)
\((2)1+3+3^{2}+3^{3}+3^{4}+…+3^{n}(\)其中\(n\)为正整数\()\).