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            • 1.

              \((1)\)若\(|a|=(2017-π)^{0}+\sin 30^{\circ}\),则\(a\)的值为________.

              \((2)\)计算\(\dfrac{a}{1-a}+\dfrac{1}{a-1}\)的结果为________.

              \((3)\)如图,设四边形\(ABCD\)是边长为\(1\)的正方形,以对角线\(AC\)为边作第二个正方形\(ACEF\),再以对角线\(AE\)为边作第三个正方形\(AEGH\),如此下去,\(….\)若正方形\(ABCD\)的边长记为\(a_{1}\),按上述方法所作的正方形的边长依次为\(a_{2}\),\(a_{3}\),\(a_{4}\),\(…\),\(a_{n}\),则\(a_{2}= \)________,\(a_{n}=\)________.

            • 2.

              计算:\(\sqrt{4}+{{(3.14-\pi )}^{0}}-\left| -2 \right|+{{(\dfrac{1}{2})}^{-1}}\)

            • 3.
              \((1)\)计算;\(( \dfrac {1}{3})^{-2}-(-1)^{2016}- \sqrt {25}+(π-1)^{0}\)
              \((2)\)化简:\( \dfrac {m^{2}-9}{3m^{2}-6m}÷(1- \dfrac {1}{m-2})\)
            • 4.

              计算:

              \((1)\left( \sqrt{48}-\sqrt{12} \right)\div 3\)        

              \((2)\left| \sqrt{2}-1 \right|+{{3}^{-2}}-\sqrt{2}+{{\left( 3-\pi \right)}^{0}}\)

            • 5.
              计算

              \((1)|-3|+(-1)^{2017}×(π-3)^{0}-{\left(- \dfrac{1}{2}\right)}^{-3} \)

              \((2)-8^{2015}×(-0.125)^{2016}+(0.25)^{3}×2^{6}\).

              \((3)100\)\({\,\!}^{2}\)\(-99\)\({\,\!}^{2}\)\(+98\)\({\,\!}^{2}\)\(-97\)\({\,\!}^{2}\)\(+…+2\)\({\,\!}^{2}\)\(-1\)\({\,\!}^{2}\)

            • 6.

              \((1)(1-π{)}^{0} =\)______________ \(;\) \({{(\dfrac{1}{3})}^{-2}}=\)_________。

              \((2)\)若分式\(\dfrac{{{x}^{2}}-1}{x+1}\)   的值为零,则\(x\)的值等于______

              \((3)\)一个多边形的内角和为\(900^{\circ}\),则这个多边形的边数为_____.

              \((4)\)等腰三角形有两条边长为\(4cm\)和\(9cm\),则该三角形的周长是_____\(cm\).

              \((5)\)若\(x^{2}+kx+4\)是完全平方式,则\(k\)的值是_____.

              \((6)\)如图,在\(Rt\triangle ABC\)中,\(∠C=90^{\circ}\),以顶点\(A\)为圆心,适当长为半径画弧,分别交\(AC\),\(AB\)于点\(M\)、\(N\),再分别以点\(M\)、\(N\)为圆心,大于\( \dfrac{1}{2} \)\(MN\)的长为半径画弧,两弧交于点\(P\),作射线\(AP\)交边\(BC\)于点\(D\),若\(CD=4\),\(AB=15\),则\(\triangle ABD\)的面积是__.



              \((7)\)如图,\(\triangle ABC\)中边\(AB\)的垂直平分线分别交\(BC\)、\(AB\)于点\(D\)、\(E\),\(AE=3cm\),\(\triangle ADC\)的周长为\(9cm\),则\(\triangle ABC\)的周长是__________\(cm\).


                                                  

              \((8)\)猜数学游戏,小明写出如下一组数:\( \dfrac{2}{5}, \dfrac{4}{7}, \dfrac{8}{11}, \dfrac{16}{19}, \dfrac{32}{35}… \)小红猜想出第六个数是\( \dfrac{64}{67} \),根据此规律第\(n\)个数是__________。

            • 7.

              \((\sqrt{7}-1)^{0}-(-\dfrac{1}{2})^{-2}+\sqrt{3}\tan 30^{\circ}\);

            • 8. \((1)\)计算:\((-2ab)(3a^{2}-2ab-b^{2})\)
              \((2)\)计算:\(2014^{0}+2^{-2}-( \dfrac {1}{2})^{2}+2013\)
              \((3)\)用乘法公式计算:\(102×98\)
              \((4)\)计算:\(2(m+1)^{2}-(2m+1)(2m-1)\)
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