共50条信息
化简求值与解方程:
\((1)(x+1+ \dfrac{1}{x-1})÷ \dfrac{{x}^{2}}{x+1} \),其中\(x=3.\) \((2) \dfrac{1-x}{x-2}+2= \dfrac{1}{x-2} \)
计算:
\((1)\)化简:\(\dfrac{xy(x+y)}{{{(x-y)}^{2}}}\cdot \dfrac{x-y}{xy+{{y}^{2}}}\) \((2)\)解分式方程:\(\dfrac{2}{x}=\dfrac{3}{x+2}\)
解分式方程:\(\dfrac{3}{6x-2}+1=\dfrac{2}{3x-1}\)
进入组卷