优优班--学霸训练营 > 知识点挑题
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            • 1.

              计算:\(2\cos 30{}^\circ +{{\left( \pi -\cos 45{}^\circ \right)}^{0}}-3\tan 30{}^\circ +{{(-\dfrac{1}{2})}^{-2}}\)

            • 2.
              \((1)\)计算:\(|45−1|45+(3−π{)}^{0}−( \dfrac{1}{2}{)}^{−1}+2{\sin }^{2}⁡{30}^{∘} \)
              \((2)\)如果关于\(x\)的不等式组\(\begin{cases} x{ > }a{+}2 \\ x{ < }3a{-}2 \end{cases}\)无解,求\(a\)的取值范围.
            • 3.

              \((1)\)计算:\(|2−\tan ⁡{60}^{∘}|−(π−3.14{)}^{0}+(− \dfrac{1}{2}{)}^{−2}+ \dfrac{1}{2} \sqrt{12} \).

              \((2)\)解方程:\((x{-}1)(x +3){=}12\).
            • 4.

              计算:\((-2018)^{0} -\sqrt{\mathbf{8}}+3\tan 30^{\circ}+|1-\sqrt{2}|\)

            • 5.
              计算:\(( \dfrac {1}{2})^{-1}+(3-π)^{\circ}-|1-\tan 60^{\circ}|+ \sqrt {12}÷2\).
            • 6.
              \((1)\)计算:\(( \sqrt {7}-1)^{0}-(- \dfrac {1}{2})^{-2}+ \sqrt {3}\tan 30^{\circ}\);
              \((2)\)解方程:\( \dfrac {x+1}{x-1}+ \dfrac {4}{1-x^{2}}=1\).
            • 7.
              计算:\(( \sqrt {2}-π)^{0}-(1-\sin 30^{\circ})^{-1}+2 \sqrt {(1-\tan 60 ^{\circ} )^{2}}\).
            • 8.

              \((\sqrt{7}-1)^{0}-(-\dfrac{1}{2})^{-2}+\sqrt{3}\tan 30^{\circ}\);

            • 9.

              \((1)\)计算:\({\left(- \dfrac{1}{3}\right)}^{-1}+{\left(2015- \sqrt{3}\right)}^{0}-4\sin 60^{\circ}+\left|- \sqrt{12}\right| \)


                \((2)\)先化简,再求值:\(\left( \dfrac{1}{a+b}- \dfrac{1}{a-b}\right)÷ \dfrac{b}{{a}^{2}-2ab+{b}^{2}} \)

            • 10. 若a=3-tan60°,则(1-
              2
              a-1
              )
              ÷
              a2-6a+9
              a-1
              =    
            0/40

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