计算题:
\((1)-{3}^{2}×{\left(- \dfrac{1}{2}\right)}^{3}-\left( \dfrac{3}{4}+ \dfrac{1}{6}- \dfrac{3}{8}\right)÷\left(- \dfrac{1}{24}\right) \).
\((2)\)先化简,再求值\(3x^{2}y-xyz-(2xyz-x^{2}z)-4x^{2}z+[3x^{2}y-(4xyz-5x^{2}z-3xyz)]\),其中\(x=-1\),\(y=2\),\(z=-3\).
\((3)\)解方程: \(\dfrac{0.4{x}+0.9}{0.5}-\dfrac{{x-5}}{{2}}=\dfrac{0.02{x}+0.03}{0.03}\)
\((4)\)解方程组:\(\begin{cases} & {x}+{y}+2{z}=7 \\ & {x}-2{y}-{z}=-4 \\ & 2{x}+3{y}+{z}=18 \end{cases}\)
\((5)\)已知关于\(x\),\(y\)的方程组\(\begin{cases} & {x}+2{y}=3{m} \\ & {x-y}=9{m} \end{cases}\)的解也是方程\(3x+2y=17\)的解,求\(m\)的值。
\((6)\)若\(x\):\(y\):\(z=3\):\(4\):\(7\),且\(2x-y+z=18\),那么\(x+2y-z\)的值是多少?