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            • 1.

              若\(\dfrac{1}{m}+\dfrac{1}{n}=\dfrac{9}{m+n}\),则\(\dfrac{n}{m}+\dfrac{m}{n}=\)__________ .

            • 2.

              \((1)\)分解因式:\(a{{x}^{2}}-6axy+9a{{y}^{2}}= \)____________________________

              \((2)\)化简:\((a+2+\dfrac{5}{2-a})\cdot \dfrac{2a-4}{a+3}= \)________________

              \((3)\)如图,在平面直角坐标系中,经过点\(A\)的双曲线\(y=\dfrac{k}{x}(k > 0)\)同时经过点\(B\),且点\(A\)在点\(B\)的左侧,点\(A\)的横坐标为\(\sqrt{2}\),\(∠AOB=∠OBA=45^{\circ}\),则\(k\)的值为_____



              \((4)\)如图,已知\(P\)是正方形\(ABCD\)外一点,且\(PA=3\),\(PB=4\) ,则\(PC\)的最大值是_______



              \((5)\)如图,一段抛物线:\(y=-{{x}^{2}}+2x(0\leqslant x\leqslant 2)\)  记为 \(C_{1}\) ,它与\(x\)轴交于两点\(O\)、\(A_{1}\);将\(C_{1}\)绕\(A_{1}\)旋转\(180^{\circ}\)得到\(C_{2}\),交\(x\)轴\(A_{2}\);将\(C_{2}\)绕\(A_{2}\)旋转\(180^{\circ}\)得到\(C_{3}\),交\(x\)轴于\(A_{3}\);\(…\)如此进行下去,直至得到\(C\)\({\,\!}_{6}\),若点\(P(11,m)\)在第\(6\)段抛物线\(C\)\({\,\!}_{6}\)上,则\(m=\)________

            • 3.
              化简:\(( \dfrac {x}{x-3}+ \dfrac {2}{3-x})⋅ \dfrac {x-3}{x-2}=\) ______ .
            • 4.

              化简或计算分式:

              \(\dfrac{ab-3{{a}^{2}}}{9{{a}^{2}}-6ab+{{b}^{2}}}=\)       


              \( \dfrac{x-3}{{x}^{2}-1}- \dfrac{2}{1+x} =\)       







              若\(m-{{m}^{-1}}=-2\),则\( \dfrac{{m}^{2}}{{m}^{4}+1} =\)                   

            • 5.

              \((1)\)计算\( \sqrt{12}- \sqrt{3} \)的结果是____________.

              \((2)\)若不等式组\(\begin{cases}5-2x\leqslant 1 \\ x-m < 0\end{cases} \)只有\(2\)个整数解,则\(m\)的取值范围是______.

              \((3)\)已知\(x+ \dfrac{1}{x}=-4 \),则\({x}^{2}+ \dfrac{1}{{x}^{2}} \)的值为______.

              \((4)\)对于\(x\)\( > 0\),规定\(f\)\((\)\(x\)\()= \dfrac{x}{x+1} \),例如\(f\)\((2)= \dfrac{2}{2+1}= \dfrac{2}{3} \),\(f( \dfrac{1}{2})= \dfrac{ \dfrac{1}{2}}{ \dfrac{1}{2}+1}= \dfrac{1}{3} \),那么\(f\)\(( \dfrac{1}{2011} )+\)\(f\)\(( \dfrac{1}{2010} )+…+\)\(f\)\(( \dfrac{1}{3} )+\)\(f\)\(( \dfrac{1}{2} )+\)\(f\)\((1)+\)\(f\)\((2)+…+\)\(f\)\((2011)= \)______.

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