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            • 1.

              若顺次连接四边形的各边中点所得的四边形是菱形,则该四边形一定是(    )

              A.矩形                             
              B.一组对边相等,另一组对边平行的四边形

              C.对角线互相垂直的四边形           
              D.对角线相等的四边形
            • 2.
              如图,在矩形\(ABCD\)中,\(AB=4\),\(BC=6\),点\(E\)为\(BC\)的中点,将\(\triangle ABE\)沿\(AE\)折叠,使点\(B\)落在矩形内点\(F\)处,连接\(CF\),则\(CF\)的长为(    )

              A.\(\dfrac{9}{5} \)
              B.\(\dfrac{18}{5} \)
              C.\(\dfrac{16}{5} \)
              D.\(\dfrac{12}{5} \)
            • 3.

              如图,正方形\(ABCD\)中,\(AD=5\),点\(E\)、\(F\)是正方形\(ABCD\)内的两点,且\(AE=FC=4\),\(BE=DF=3\),则以\(EF\)为直径的圆的面积为 【 】


              A.\(\dfrac{1}{2}\pi \)
              B.\(\dfrac{3}{5}\pi \)

              C.\(\dfrac{3}{4}\pi \)
              D.\(\pi \)
            • 4.

              下列说法:\(①\)同位角相等;\(②\)矩形的对角线相等;\(③\)相似三角形对应边的比等于对应高的比;\(④\)方程\(x^{2}=3x\)的解是\(x=3\);\(⑤\)相等的圆心角所对的弧相等;\(⑥\)三角形的外心到三边的距离相等;其中正确的个数有(    )

              A.\(1\)     
              B.\(2\)
              C.\(3\)
              D.\(4\)
            • 5.

              如图,在四边形\(ABCD\)中,\(AB/\!/CD\),\(∠B=90^{\circ}\),\(AB=AD=5\),\(BC=4\),\(M\)、\(N\)、\(E\)分别是\(AB\)、\(AD\)、\(CB\)上的点,\(AM=CE=1\),\(AN=3\),点\(P\)从点\(M\)出发,以每秒\(1\)个单位长度的速度沿折线\(MB-BE\)向点\(E\)运动,同时点\(Q\)从点\(N\),以相同的速度沿折线\(ND-DC-CE\)向点\(E\)运动,设\(\triangle APQ\)的面积为\(S\),运动的时间为\(t\)秒,则\(S\)与\(t\)函数关系的大致图象为(    )


              A.
              B.
              C.
              D.
            • 6.

              如图,矩形\(ABCD\)中,对角线\(AC\)、\(BD\)相交于点\(O\),过点\(O\)作\(OE⊥BD\)交\(AD\)于点\(E.\)已知\(AB=2\),\(\triangle DOE\)的面积为\( \dfrac{5}{4} \),则\(AE\)的长为\((\)           \()\)


              A. \(\sqrt{5}\)
              B.\(1.5\)
              C.\(2\)
              D.\(\sqrt{2}\)
            • 7.

              如图,在矩形\(ABCD\)中,\(AB=3\),\(AD=4\),\(P\)是\(AD\)上一动点,\(PF⊥BD\)于\(F\),\(PE⊥AC\)于\(E\),则\(PE+PF\)的值为(    )


              A.\( \dfrac{12}{5}\)
              B.\( \dfrac{13}{5}\)
              C.\( \dfrac{5}{2}\)
              D.\(2\)
            • 8.
              如图,将矩形\(ABCD\)沿\(AF\)折叠,使点\(D\)落在\(BC\)边的点\(E\)处,过点\(E\)作\(EG/\!/CD\)交\(AF\)于点\(G\),连接\(DG.\)给出以下结论:\(①DG=DF\);\(②\)四边形\(EFDG\)是菱形;\(③EG^{2}= \dfrac {1}{2}GF×AF\);\(④\)当\(AG=6\),\(EG=2 \sqrt {5}\)时,\(BE\)的长为\( \dfrac {12}{5} \sqrt {5}\),其中正确的结论个数是\((\)  \()\)
              A.\(1\)
              B.\(2\)
              C.\(3\)
              D.\(4\)
            • 9.

              如图,在平面直角坐标系中,\(\odot M\)与\(x\)轴相切于点\(A(8,0)\),与\(y\)轴分别交于点\(B(0,4)\)与点\(C(0,16)\),则圆心\(M\)到坐标原点\(O\)的距离是\((\)    \()\)

              A. \(10\)         
              B.\(8\sqrt{2}\)
              C.\(4\sqrt{13}\)
              D.\(2\sqrt{41}\)
            • 10.

              如图,\(\triangle \)\(ABC\)中,\(AD\)\(⊥\)\(BC\)\(D\)\(BD\)\(=\)\(AD\)\(=8\),\(DC\)\(=6\),\(P\)为边\(AC\)上一动点,\(PE\)\(⊥\)\(AB\)\(PF\)\(⊥\)\(BC\)\(F\),连接\(EF\),则\(EF\)的最小值为\((\)   \()\)


              A.\( \dfrac{28 \sqrt{2}}{5} \)
              B.\( \dfrac{56}{5} \)
              C.\( \dfrac{14 \sqrt{2}}{2} \)
              D.\(6\)
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