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            • 1.
              如图,在菱形\(ABCD\)中,\(∠DAB=60^{\circ}\),现把菱形\(ABCD\)绕点\(A\)逆时针方向旋转\(30^{\circ}\)得到菱形\(AB′C′D′\),若\(AB=4\),则阴影部分的面积为\((\)  \()\)
              A.\(4π-12 \sqrt {3}+12\)
              B.\(4π-8 \sqrt {3}+12\)
              C.\(4π-4 \sqrt {3}\)
              D.\(4π+12\)
            • 2.
              如图\(1\),在\(Rt\triangle ABC\)中,\(∠A=90^{\circ}\),\(AB=AC\),点\(D\),\(E\)分别在边\(AB\),\(AC\)上,\(AD=AE\),连接\(DC\),点\(M\),\(P\),\(N\)分别为\(DE\),\(DC\),\(BC\)的中点.
              \((1)\)观察猜想
                       图\(1\)中,线段\(PM\)与\(PN\)的数量关系是 ______ ,位置关系是 ______ ;
              \((2)\)探究证明
                     把\(\triangle ADE\)绕点\(A\)逆时针方向旋转到图\(2\)的位置,连接\(MN\),\(BD\),\(CE\),判断\(\triangle PMN\)的形状,并说明理由;
              \((3)\)拓展延伸
                      把\(\triangle ADE\)绕点\(A\)在平面内自由旋转,若\(AD=4\),\(AB=10\),请直接写出\(\triangle PMN\)面积的最大值.
            • 3.

              在\(Rt\triangle ABC\)中, \(∠ACB=90^{\circ}\),\(CD\)是\(AB\)边的中线,\(DE⊥BC\)于\(E\), 连结\(CD\),点\(P\)在射线\(CB\)上\((\)与\(B\),\(C\)不重合\()\).


              \((1)\)如果\(∠A=30^{\circ}\)

              \(①\)如图\(1\),\(∠DCB= \)_________\({\,\!}^{\circ}\)

              \(②\)如图\(2\),点\(P\)在线段\(CB\)上,连结\(DP\),将线段\(DP\)绕点\(D\)逆时针旋转\(60^{\circ}\),得到线段\(DF\),连结\(BF\),补全图\(2\)猜想\(CP\)、\(BF\)之间的数量关系,并证明你的结论;

              \(( 2 )\)如图\(3\),若点\(P\)在线段\(CB\) 的延长线上,且\(∠A=\alpha \) \((0^{\circ} < \alpha < 90^{\circ})\) ,连结\(DP\), 将线段\(DP\)绕点逆时针旋转\(2\alpha \)得到线段\(DF\),连结\(BF\), 请直接写出\(DE\)、\(BF\)、\(BP\)三者的数量关系\((\)不需证明\()\).

            • 4.
              如图,正方形\(ABCD\)中,\(AB=3cm\),以\(B\)为圆心,\(1cm\)长为半径画\(⊙B\),点\(P\)在\(⊙B\)上移动,连接\(AP\),并将\(AP\)绕点\(A\)逆时针旋转\(90^{\circ}\)至\(AP′\),连接\(BP′.\)在点\(P\)移动的过程中,\(BP′\)长度的最小值为 ______ \(cm\).
            • 5.
              如图,在\(Rt\triangle AOB\)中,\(∠AOB=90^{\circ}\),\(OA=3\),\(OB=2\),将\(Rt\triangle AOB\)绕点\(O\)顺时针旋转\(90^{\circ}\)后得\(Rt\triangle FOE\),将线段\(EF\)绕点\(E\)逆时针旋转\(90^{\circ}\)后得线段\(ED\),分别以\(O\),\(E\)为圆心,\(OA\)、\(ED\)长为半径画弧\(AF\)和弧\(DF\),连接\(AD\),则图中阴影部分面积是 ______ .
            • 6.
              如图,边长为\(2 \sqrt {2}\)的正方形\(ABCD\)中,\(P\)是对角线\(AC\)上的一个动点\((\)点\(P\)与\(A\)、\(C\)不重合\()\),连接\(BP\),将\(BP\)绕点\(B\)顺时针旋转\(90^{\circ}\)到\(BQ\);连接\(PQ\),\(PQ\)与\(BC\)交于点\(E\),\(QP\)延长线与\(AD(\)或\(AD\)延长线\()\)交于点\(F\),连接\(CQ.\)求证:
              \((\)Ⅰ\()CQ=AP\);
              \((\)Ⅱ\()\triangle APB\)∽\(\triangle CEP\).
            • 7.
              如图,在\(Rt\triangle ABC\)中,\(∠C=90^{\circ}\),\(AC=6\),\(BC=8\),把\(\triangle ABC\)绕\(AB\)边上的点\(D\)顺时针旋转\(90^{\circ}\)得到\(\triangle A′B′C′\),\(A′C′\)交\(AB\)于点\(E\),若\(AD=BE\),则\(\triangle A′DE\)的面积是\((\)  \()\)
              A.\(3\)
              B.\(5\)
              C.\(11\)
              D.\(6\)
            • 8.
              如图,\(Rt\triangle ABC\)中,\(∠BAC=90^{\circ}\),将\(\triangle ABC\)绕点\(C\)逆时针旋转,旋转后的图形是\(\triangle A′B′C\),点\(A\)的对应点\(A′\)落在中线\(AD\)上,且点\(A′\)是\(\triangle ABC\)的重心,\(A′B′\)与\(BC\)相交于点\(E\),那么\(BE\):\(CE=\) ______ .
            • 9.
              如图,\(\triangle ABC\)中,\(AB=6\),\(DE/\!/AC\),将\(\triangle BDE\)绕点\(B\)顺时针旋转得到\(\triangle BD′E′\),点\(D\)的对应点\(D′\)落在边\(BC\)上\(.\)已知\(BE′=5\),\(D′C=4\),则\(BC\)的长为 ______ .
            • 10.
              正方形\(ABCD\)的边长为\(3\),\(E\)、\(F\)分别是\(AB\)、\(BC\)边上的点,且\(∠EDF=45^{\circ}.\)将\(\triangle DAE\)绕点\(D\)逆时针旋转\(90^{\circ}\),得到\(\triangle DCM\).
              \((1)\)求证:\(EF=FM\);
              \((2)\)当\(AE=1\)时,求\(EF\)的长.
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