如图,在数轴上\(A\),\(B\)两点对应的数分别是\(6\), \(-6\),\(\angle DCE=90{}^\circ (C\)与\(O\)重合,\(D\)点在数轴的正半轴上\()\)
\((1)\)如图\(1\),若\(CF\) 平分\(\angle ACE\),则\(\angle AOF=\)_________\(;\)
\((2)\)如图\(2\),将\(\angle DCE\)沿数轴的正半轴向右平移\(t(0 \) 逆时针旋转\(30t\)度,作\(CF\)平分\(\angle ACE\),此时记\(\angle DCF=\alpha \).
\(①\)当\(t=1\)时,\(\alpha {=}\) _______\(;\)
\(②\)猜想\(\angle BCE\)和\(\alpha \)的数量关系,并证明\(;\)
\((3)\)如图\(3\),开始\(\angle {{D}_{1}}{{C}_{1}}{{E}_{1}}\)与\(\angle DCE\)重合,将\(\angle DCE\)沿数轴的正半轴向右平移\(t(0 < t < 3)\)个单位,再绕点顶点\(C\)逆时针旋转\(30t\)度,作\(CF\)平分\(\angle ACE\),此时记\(\angle DCF=\alpha \),与此同时,将\(\angle {{D}_{1}}{{C}_{1}}{{E}_{1}}\)沿数轴的负半轴向左平移\(t(0 < t < 3)\)个单位,再绕点顶点\({{C}_{1}}\)顺时针旋转\(30t\)度,作\({{C}_{1}}{{F}_{1}}\)平分\(\angle A{{C}_{1}}{{E}_{1}}\),记\(\angle {{D}_{1}}{{C}_{1}}{{F}_{1}}=\beta \),若\(\alpha \)与\(\beta \)满足\(\left| \alpha -\beta \right|=20{}^\circ \),请直接写出\(t\)的值为_________.