优优班--学霸训练营 > 知识点挑题
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            • 1.

              下列运算正确的是

              A.\({{(2{{a}^{2}})}^{3}}=6{{a}^{6}}\)
              B.\({{a}^{3}}\cdot {{a}^{2}}={{a}^{5}}\)
              C.\(2{{a}^{2}}+4{{a}^{2}}=6{{a}^{4}}\)
              D.\({{(a+2b)}^{2}}={{a}^{2}}+4{{b}^{2}}\)
            • 2.
              \(x^{5}⋅(x^{m})^{n}\)的计算结果是\((\)  \()\)
              A.\(x^{m+n+5}\)
              B.\(x^{5mn}\)
              C.\(x^{5+mn}\)
              D.\(x^{3(m+n)}\)
            • 3.
              \(a^{m}=2\),\(a^{n}=3\),则\(a^{m+n}=\) ______ .
            • 4.
              下列计算正确的是\((\)  \()\)
              A.\(a^{3}⋅a^{3}=2a^{3}\)
              B.\(a^{3}÷a=a^{3}\)
              C.\(a+a=2a\)
              D.\((a^{3})^{2}=a^{5}\)
            • 5.

              下列各式计算正确的是

              A.\({{a}^{2}}+2{{a}^{3}}=5{{a}^{5}}\)
              B.\(a\cdot {{a}^{2}}={{a}^{3}}\)
              C.\({{a}^{6}}\div {{a}^{2}}={{a}^{3}}\)
              D.\({{({{a}^{2}})}^{3}}={{a}^{5}}\)
            • 6.
              下列等式成立的是\((\)  \()\)
              A.\(a^{2}⋅a^{5}=a^{10}\)
              B.\( \sqrt {a+b}= \sqrt {a}+ \sqrt {b}\)
              C.\((-a^{3})^{6}=a^{18}\)
              D.\( \sqrt {a^{2}}=a\)
            • 7.

              计算:\(\dfrac{ \overset{9个a}{\overbrace {a+a+…+a}}}{ \overset{\underbrace {b·b·b…b}}{7个b}} =\)

              A.\(\dfrac{9a}{7b}\)
              B.\(\dfrac{{{a}^{9}}}{7b}\)
              C.\(\dfrac{9a}{{{b}^{7}}}\)
              D.\(\dfrac{{{a}^{9}}}{{{b}^{7}}}\)
            • 8.
              下列运算正确的是\((\)  \()\)
              A.\(6a-5a=1\)
              B.\(a^{2}⋅a^{3}=a^{5}\)
              C.\((a^{2})^{3}=a^{5}\)
              D.\(a^{6}÷a^{3}=a^{2}\)
            • 9.
              计算:
              \(2^{n}×2^{2n+1}=\) ______ .
            • 10.
              计算:
              \((1)3^{4}×3^{6}\)
              \((2)a^{2}×(-a)^{2}\)
              \((3)(3ab^{7})^{2}\)
              \((4)(x-y)^{3}(x-y)^{2}\)
              \((5)(x^{2})^{5}×(-x)^{5}\)
              \((6)(m^{4})^{2}+m^{5}⋅m^{3}+(-m)^{4}⋅m^{4}\).
            0/40

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