共50条信息
计算:
\((1)(-\dfrac{1}{5}a^{3}x^{4}-\dfrac{9}{10}a^{2}x^{3})÷(-\dfrac{3}{5}ax^{2})\);
\((2)(2x-y)(4x\)\({\,\!}^{2}\)\(-y\)\({\,\!}^{2}\)\()(2x+y)\);\((3)[(x+y)\)\({\,\!}^{2}\)\(-(x-y)\)\({\,\!}^{2}\)\(]÷2xy\).
\(28a^{4}b^{2}÷7ab\)的结果是( ).
\((1){{(-\dfrac{n}{m})}^{-3}}\);
\((2)(3x^{2}y^{-2})^{-3}\);
\((3)\dfrac{3{{x}^{-2}}{{y}^{-3}}}{4{{x}^{-5}}{{y}^{2}}}\);
\((4)5a^{-5}b^{2}-(2ab^{-1})^{2}\);
\((5)(m^{3}n)^{-2}·(2m^{-2}n^{-3})^{-2}\).
\(-4x\)\({\,\!}^{4}\)\(y\)\({\,\!}^{2}\)\(z\)\({\,\!}^{2}\)\(÷(-\)\( \dfrac{1}{2} \)\(x\)\({\,\!}^{3}\)\(yz)\)的结果是( ).
已知一个单项式乘以\(\dfrac{1}{2}{{a}^{2}}{{b}^{5}}c\)所得的积是\(-\dfrac{2}{3}{{a}^{4}}{{b}^{5}}{{c}^{2}}\),求这个单项式.
已知\(28\)\(a\)\({\,\!}^{2}\)\(b\)\({\,\!}^{m}÷4\)\(a\)\({\,\!}^{n}\)\(b\)\({\,\!}^{2}=7\)\(b\)\({\,\!}^{2}\),那么\(m\),\(n\)的值为\((\) \()\)
进入组卷