共50条信息
如图,在\(□\)\(ABCD\)中,\(E\)是\(BC\)边的中点,\(F\)是对角线\(AC\)的中点,若\(EF=5\),则\(DC\)的长为
如图,在\(\triangle ABC\)中,\(∠C=90^{\circ}\),以\(BC\)为直径的\(⊙O\)交\(AB\)于点\(D\),\(⊙O\)的切线\(DE\)交\(AC\)于点\(E\).
\((1)\)求证:\(E\)是\(AC\)中点;
\((2)\)若\(AB=10\),\(BC=6\),连接\(CD\),\(OE\),交点为\(F\),求\(OF\)的长.
如图,等边三角形\(ABC\)中, \(D\),\(E\)分别是\(AB\),\(AC\)的中点,延长\(BC\)至点\(F\),使\(CF=\dfrac{1}{2}BC\),连接\(DE\),\(CD\),\(EF\).
\((1)\)求证:四边形\(DCFE\)是平行四边形;
\((2)\)若等边三角形\(ABC\)的边长为\(a\),写出求\(EF\)长的思路.
进入组卷