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            • 1. 把一张对面互相平行的纸条折成如图所示那样,\(EF\)是折痕,若\({∠}{EFB}{=}32^{{∘}}\)则下列结论正确的有


              \(({  })(1){∠}C{{{{"}}}}{EF}{=}32^{{∘}}(2){∠}{AEC}{=}116^{{∘}}(3){∠}{BGE}{=}64^{{∘}}(4){∠}{BFD}{=}116^{{∘}}\).

              A.\(1\)个                          
              B.\(2\)个                           
              C.\(3\)个                           
              D.\(4\)
            • 2.

              如图,在等腰直角\(\Delta ABC\)中,\(\angle C=90{}^\circ \),\(D\)为\(BC\)的中点,将\(\Delta ABC\)折叠,使点\(A\)与点\(D\)重合,\(EF\)为折痕,则\(\sin \angle BED\)的值是    \((\)         \()\)

              A.\(\dfrac{\sqrt{5}}{5}\)
              B.\(\dfrac{3}{5}\)
              C.\(2\sqrt{2}\)
              D.\(\dfrac{2}{3}\)
            • 3.

              把等腰\(\triangle ABC\)沿底边\(BC\)翻折,得到\(\triangle DBC\),那么四边形\(ABDC\)(    ).


              A.是中心对称图形,不是轴对称图形    
              B.不是中心对称图形,是轴对称图形

              C.既是中心对称图形,又是轴对称图形  
              D.既不是中心对称图形,也不是轴对称图形
            • 4.
              如图,有一张直角三角形纸片,两直角边\(AC=5cm\),\(BC=10cm\),将\(\triangle ABC\)折叠,点\(B\)与点\(A\)重合,折痕为\(DE\),则\(CD\)的长为\((\)  \()\)
              A.\( \dfrac {25}{2}\)
              B.\( \dfrac {15}{2}\)
              C.\( \dfrac {25}{4}\)
              D.\( \dfrac {15}{4}\)
            • 5.

              如图,在\(Rt\triangle ABC\)中,\(∠C=90^{\circ}\),\(AC=BC\)\(=6cm\),点\(P\) 从点\(B\)出发,沿\(BA\)方向以每秒\( \sqrt[]{2}cm\)的速度向终点\(A\)运动;同时,动点\(Q\)从点\(C\)出发沿\(CB\)方向以每秒\(1cm\) 的速度向终点\(B\)运动,将\(\triangle BPQ\)沿\(BC\)翻折,点\(P\)的对应点为点\(P′\),设\(Q\)点运动的时间\(t\)秒,若四边形\(QPBP′\)为菱形,则\(t\)的值为\((\)    \()\)




              A.\(2\)
              B.\( \sqrt[]{2}\)
              C.\(2 \sqrt{2} \)
              D.\(4\)
            • 6.
              如图,在菱形纸片\(ABCD\)中,\(∠A=60^{\circ}\),将纸片折叠,点\(A\)、\(D\)分别落在点\(A′\)、\(D′\)处,且\(A′D′\)经过点\(B\),\(EF\)为折痕,当\(D′F⊥CD\)时,\( \dfrac {CF}{FD}\)的值为\((\)  \()\)
              A.\( \dfrac { \sqrt {3}-1}{2}\)
              B.\( \dfrac { \sqrt {3}}{6}\)
              C.\( \dfrac {2 \sqrt {3}-1}{6}\)
              D.\( \dfrac { \sqrt {3}+1}{8}\)
            • 7.
              如图,正\(\triangle ABC\)的边长为\(2\),过点\(B\)的直线\(l⊥AB\),且\(\triangle ABC\)与\(\triangle A′BC′\)关于直线\(l\)对称,\(D\)为线段\(BC′\)上一动点,则\(AD+CD\)的最小值是\((\)  \()\)
              A.\(4\)
              B.\(3 \sqrt {2}\)
              C.\(2 \sqrt {3}\)
              D.\(2+ \sqrt {3}\)
            • 8.
              如图,在平面直角坐标系中,点\(A(0,4)\)、\(B(3,0)\),连接\(AB\),将\(\triangle AOB\)沿过点\(B\)的直线折叠,使点\(A\)落在\(x\)轴上的点\(A′\)处,折痕所在的直线交\(y\)轴正半轴于点\(C\),则直线\(BC\)的解析式为\((\)  \()\)
              A.\(y=- \dfrac {1}{2}x+ \dfrac {2}{3}\)
              B.\(y=-x+ \dfrac {2}{3}\)
              C.\(y=- \dfrac {1}{2}x+ \dfrac {3}{2}\)
              D.\(y=-2x+ \dfrac {3}{2}\)
            • 9.
              将矩形纸片\(ABCD\)按如图所示的方式折叠,恰好得到菱形\(AECF.\)若\(AB=3\),则菱形\(AECF\)的面积为\((\)  \()\)
              A.\(1\)
              B.\(2 \sqrt {2}\)
              C.\(2 \sqrt {3}\)
              D.\(4\)
            • 10.

              在▱\(ABCD\)中,\(∠\)\(ACB\)\(={{25}^{0}}\) ,现将▱\(ABCD\)沿\(EF\)折叠,使点\(C\)与点\(A\)重合,点\(D\)落在\(G\)处,则\(∠\)\(GFE\)的度数\((\)    \()\)


              A. \(135^{∘}\)
              B.\(120^{∘}\)
              C.\(115^{∘}\)
              D.\(100^{∘}\)
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