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            • 1.

              如图,在\(\triangle ABC\)中,\(D\),\(E\)分别是\(AB\),\(AC\)边上的点,\(DE/\!/BC.\)若\(AD=6\),\(BD=2\), \(DE=3\),则\(BC=\)_______.

            • 2.

              如图,已知\(ED/\!/BC\),点\(A\)在\(ED\)上,点\(C\)在\(DF\)上,\(∠EAB=∠BCF\),且\(E\)、\(B\)、\(F\)、\(O\)四点共线.

              \((1)\)四边形\(ABCD\)为平行四边形;

              \((2)\)已知\(OF=3\),\(OE=12\),求\(OB\)的值.

            • 3.
              如图,正方形\(ABCD\)中,\(BC=2\),点\(M\)是边\(AB\)的中点,连接\(DM\),\(DM\)与\(AC\)交于点\(P\),点\(E\)在\(DC\)上,点\(F\)在\(DP\)上,且\(∠DFE=45^{\circ}.\)若\(PF= \dfrac{ \sqrt{5}}{6} \),则\(CE= \)______ .
            • 4.

              如图,点\(A\)在反比例函数\(y=-\dfrac{3}{x}\)的图象上,点\(B\)在反比例函数\(y=\dfrac{k}{x}\)的图象上,\(AB/\!/x\)轴,连接\(OB\),过点\(A\)作\(AC⊥x\)轴于点\(C\),交\(OB\)于点\(D\),若\(AD=2DC\),则\(k\)的值为            

            • 5.

              如图,\(\triangle OAB\)中,\(∠OAB=90∘\),\(OA=AB=1.\)以\(OB\)为直角边向外作等腰直角三角形\(OBB_{1}\),以\(OB_{1}\)为直角边向外作等腰直角三角形\(OB_{1}B_{2}\),以\(OB_{2}\)为直角边向外作等腰直角三角形\(OB_{2}B_{3}\),\(…\),连接\(AB_{1,}BB_{2}\),\(B_{1}B_{3}\),\(…\),分别与\(OB\),\(OB_{1}\),\(OB_{2}\),\(…\)交于点\(C_{1}\),\(C_{2}\),\(C_{3}\),\(…\),按此规律继续下去,\(\triangle ABC_{1}\)的面积记为\(S_{1}\),\(\triangle BB_{1}C_{2}\)的面积记为\(S_{2}\),\(\triangle B_{1}B_{2}C_{3}\)的面积记为\(S_{3}\),\(…\),则\(S_{2018}=(\)      \()\)


              A.\(\dfrac{1}{3}\times {{2}^{2015}}\)
              B.\(\dfrac{1}{3}\times {{2}^{2016}}\)
              C.\(\dfrac{1}{3}\times {{2}^{2017}}\)
              D.\(\dfrac{1}{3}\times {{2}^{2018}}\)
            • 6.
              如图,在\(\triangle ABC\)中,点\(D\)、\(E\)分别在边\(AB\)、\(AC\)的反向延长线上,下面比例式中,不能判断\(ED/\!/BC\)的是

                                                             

              A.\( \dfrac{BA}{BD}= \dfrac{CA}{CE} \)
              B.\( \dfrac{EA}{EC}= \dfrac{DA}{DB} \)
              C.\( \dfrac{ED}{BC}= \dfrac{EA}{AC} \)
              D.\( \dfrac{EA}{AD}= \dfrac{AC}{AB} \)    
            • 7.

              如图,在\(\triangle ABC\)中,\(D\),\(E\)分别为\(AB\),\(AC\)边上的点,\(DE/\!/BC\),\(BE\)与\(CD\)相交于点\(F\),则下列结论一定正确的是(    )


              A.\( \dfrac{AD}{AB}= \dfrac{AE}{AC} \)
              B.\( \dfrac{DF}{FC}= \dfrac{AE}{EC} \)
              C.\( \dfrac{AD}{DB}= \dfrac{DE}{BC} \)
              D.\( \dfrac{DF}{BF}= \dfrac{EF}{FC} \)
            • 8.

              如图,在边长为\(\sqrt{3}+1\)的菱形\(ABCD\)中,\(∠A=60^{\circ}\),点\(E\),\(F\)分别在\(AB\),\(AD\)上,沿\(EF\)折叠菱形,使点\(A\)落在\(BC\)边上的点\(G\)处,且\(EG⊥BD\)于点\(M\),则\(EG\)的长为(    )


              A.\(1\)
              B.\(1\)
              C.\(\sqrt{3}\)
              D.\(\dfrac{\sqrt{3}{+}1}{2}\)
            • 9.

              如图,已知\(AD/\!/EF/\!/BC\),如果\(AE︰EB=2︰3\),\(FC=6\),那么\(DC=\)________.

            • 10.

              已知正方形\(ABCD\),\(P\)为射线\(AB\)上的一点,以\(BP\)为边作正方形\(BPEF\),使点\(F\)在线段\(CB\)的延长线上,连接\(EA\),\(EC\).

              \((1)\)如图\(1\),若点\(P\)在线段\(AB\)的延长线上,求证:\(ΔAPE\)≌\(ΔCFE\);

              \((2)\)如图\(2\),若点\(P\)在线段\(AB\)的中点,连接\(AC\),判断\(\triangle ACE\)的形状,并说明理由;

              \((3)\)如图\(3\),若点\(P\)在线段\(AB\)上,连接\(AC\),当\(EP\)平分\(∠AEC\)时,设\(AB=a\),\(BP=b\),\(①\)求\(a\):\(b\)的值;\(②\)求\(∠AEC\)的度数.

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