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            • 1.
              在\(4×4\)的正方形网格中,\(\triangle ABC\)和\(\triangle DEF\)的顶点都在边长为\(1\)的正方形的顶点上,则图中\(∠ACB\)的正切值为\((\)  \()\)
              A.\( \dfrac {2}{3}\)
              B.\( \dfrac {1}{3}\)
              C.\( \dfrac { \sqrt {2}}{2}\)
              D.\(3\)
            • 2.
              如图,\(O\)为坐标原点,点\(B\)在\(x\)轴的正半轴上,四边形\(OBCA\)是平行四边形,\(\sin ∠AOB= \dfrac {4}{5}\),反比例函数\(y= \dfrac {m}{x}(m > 0)\)在第一象限内的图象经过点\(A\),与\(BC\)交于点\(F\),若点\(F\)为\(BC\)的中点,且\(\triangle AOF\)的面积为\(12\),则\(m\)的值为\((\)  \()\)
              A.\(16\)
              B.\(24\)
              C.\(36\)
              D.\(48\)
            • 3.
              如图,点\(P\)在等边\(\triangle ABC\)的内部,且\(PC=6\),\(PA=8\),\(PB=10\),将线段\(PC\)绕点\(C\)顺时针旋转\(60^{\circ}\)得到\(P{{"}}C\),连接\(AP{{"}}\),则\(\cos ∠PAP{{"}}\)的值为等于\((\)  \()\)
              A.\( \dfrac {4}{5}\)
              B.\( \dfrac {3}{5}\)
              C.\( \dfrac {3}{4}\)
              D.\( \dfrac { \sqrt {3}}{2}\)
            • 4.
              在\(Rt\triangle ABC\)中,\(∠C=90^{\circ}\),\(\sin A= \dfrac {3}{5}\),\(BC=6\),则\(AB=(\)  \()\)
              A.\(4\)
              B.\(6\)
              C.\(8\)
              D.\(10\)
            • 5.
              如图,\(\triangle ABC\)的顶点都在正方形网格的格点上,则\(\tan ∠BAC\)的值为\((\)  \()\)
              A.\(2\)
              B.\( \dfrac {1}{2}\)
              C.\( \dfrac { \sqrt {5}}{5}\)
              D.\( \dfrac { \sqrt {10}}{10}\)
            • 6.
              如图,在\(Rt\triangle ABC\)中,\(∠C=90^{\circ}\),\(∠B=30^{\circ}\),\(AB=8\),则\(BC\)的长是\((\)  \()\)
              A.\( \dfrac {4 \sqrt {3}}{3}\)
              B.\(4\)
              C.\(8 \sqrt {3}\)
              D.\(4 \sqrt {3}\)
            • 7.
              如图,在等腰\(Rt\triangle ABC\)中,\(∠C=90^{\circ}\),\(AC=6\),\(D\)是\(AC\)上一点,若\(\tan ∠DBA= \dfrac {1}{5}\),则\(AD\)的长为\((\)  \()\)
              A.\(2\)
              B.\( \sqrt {3}\)
              C.\( \sqrt {2}\)
              D.\(1\)
            • 8.
              如图,\(AB\)是\(⊙O\)的直径,弦\(CD⊥AB\)于点\(G\),点\(F\)是\(CD\)上一点,且满足\( \dfrac {CF}{FD}= \dfrac {1}{3}\),连接\(AF\)并延长交\(⊙O\)于点\(E\),连接\(AD\),\(DE\),若\(CF=2\),\(AF=3.\)给出下列结论:
              \(①\triangle ADF\)∽\(\triangle AED\); \(②FG=2\);\(③\tan ∠E= \dfrac { \sqrt {5}}{2}\); \(④S_{\triangle DEF}=4 \sqrt {5}\)
              其中正确的是\((\)  \()\)
              A.\(①②③\)
              B.\(①②④\)
              C.\(②③④\)
              D.\(①②③④\)
            • 9. 如图,两条宽为1的带子,相交成α角,那么重叠部分的面积即阴影部分的面积为(  )
              A.sinα
              B.
              1
              sinα
              C.
              1
              sin2α
              D.
              1
              cosα
            • 10. 如图,已知AB是⊙O的直径,弦CD⊥AB,AC=2
              2
              ,BC=1,那么sin∠ABD的值是(  )
              A.
              2
              2
              3
              B.
              2
              4
              C.
              2
              3
              D.2
              2
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