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            • 1.
              在\(Rt\triangle ABC\)中,\(∠C=90^{\circ}\),\(\tan A= \dfrac {2}{3}\),\(AC=6\),则\(BC=(\)  \()\)
              A.\(9\)
              B.\(4\)
              C.\(18\)
              D.\(12\)
            • 2.

              如图,若\(\triangle ABC\)和\(\triangle DEF\)的面积分别为\(S_{1}\)、\(S_{2}\),则  \((\)    \()\)




              A.\(S_{1}=S_{2}\)
              B.\(S_{1} > S_{2}\)
              C.\(S_{1} < S_{2}\)
              D.\(S_{1}\)与\(S_{2}\)大小不确定
            • 3. 如图,在半径为\(6cm\)的\(⊙O\)中,点\(A\)是劣弧\(\overparen {BC} \)的中点,点\(D\)是优弧\(\overparen {BC} \)上一点,且\(∠D=30^{\circ}\),下列四个结论:

              \(①OA⊥BC\);\(②BC=\)\(6\sqrt{3}\)\(cm\);\(③\sin ∠AOB=\)\(\dfrac{\sqrt{3}}{2}\);\(④\)四边形\(ABOC\)是菱形.

              其中正确结论的序号是:


              A.\(①③\)
              B.\(①②③④\)
              C.\(②③④\)
              D.\(①③④\)
            • 4.
              如图,在\(\triangle ABC\)中,\(∠B=90^{\circ}\),\(\tan ∠C= \dfrac {3}{4}\),\(AB=6cm.\)动点\(P\)从点\(A\)开始沿边\(AB\)向点\(B\)以\(1cm/s\)的速度移动,动点\(Q\)从点\(B\)开始沿边\(BC\)向点\(C\)以\(2cm/s\)的速度移动\(.\)若\(P\),\(Q\)两点分别从\(A\),\(B\)两点同时出发,在运动过程中,\(\triangle PBQ\)的最大面积是\((\)  \()\)
              A.\(18cm^{2}\)
              B.\(12cm^{2}\)
              C.\(9cm^{2}\)
              D.\(3cm^{2}\)
            • 5.

              如图,若\(∆\)\(ABC\)和\(∆\)\(DEF\)的面积分别为\(S\)\({\,\!}_{1}\),\(S\)\({\,\!}_{2}\),则


              A.\(S\)\({\,\!}_{1}=\dfrac{1}{2}\) \(S\)\({\,\!}_{2}\)
              B.\(S\)\({\,\!}_{1}=\dfrac{7}{2}\) \(S\)\({\,\!}_{2\;\;\;\;\;\;\;\;\;\;}\)
              C.\(S\)\({\,\!}_{1}=\) \(S\)\({\,\!}_{2}\)
              D.\(S\)\({\,\!}_{1}=\dfrac{8}{5}\) \(S\)\({\,\!}_{2}\)
            • 6.

              如图,将放置于平面直角坐标系中的三角板\(AOB\)绕\(O\)点顺时针旋转\(90^{\circ}\)得\(\triangle A′OB′.\)已知\(∠AOB=30^{\circ}\),\(∠B=90^{\circ}\),\(AB=1\),则\(B′\)点的坐标为(    )

              A.\(\left( \dfrac{ \sqrt{3}}{2}, \dfrac{1}{2}\right) \)
              B.\(\left( \dfrac{3}{2}, \dfrac{ \sqrt{3}}{2}\right) \)
              C.\(\left( \dfrac{1}{2}, \dfrac{ \sqrt{3}}{2}\right) \)
              D.\(\left( \dfrac{ \sqrt{3}}{2}, \dfrac{3}{2}\right) \)     
            • 7. 如图,\(AC=CE\),\(∠ACE=90^{\circ}\),\(AB⊥BD\),\(ED⊥BD\),\(AB=6cm\),\(DE=2cm\),则\(BD\)等于\((\)  \()\)
              A.\(6cm\)
              B.\(8cm\)
              C.\(10cm\)
              D.\(4cm\)
            • 8.

              如图,从\(⊙O\)外一点\(P\)引圆的两条切线\(PA\)、\(PB\),切点为\(A\)、\(B\),点\(C\)是劣弧\(AB\)上一点,过\(C\)的切线交\(PA\)、\(PB\)分别于\(M\)、\(N\),若\(⊙O\)的半径为\(2\),\(∠P=60^{\circ}\),则\(\triangle PMN\)的周长为(    )





              A.\(4\)    
              B.\(6\)       
              C.\(4 \sqrt{3} \)
              D.\(6 \sqrt{3} \)
            • 9.
              如图,\(\triangle ABC\)中,\(AB=AC\),\(∠BAC=120^{\circ}\),\(AD⊥BC\)于\(D\),\(DE⊥AB\)于\(E\),若\(AB=20cm\),则\(DE\)的长为\((\)  \()\)
              A.\(10cm\)
              B.\(5cm\)
              C.\(10 \sqrt {3}cm\)
              D.\(5 \sqrt {3}cm\)
            • 10.
              直线\(y= \dfrac {1}{2}x\)和直线\(y=-x+3\)所夹锐角为\(α\),则\(\sin α\)的值为\((\)  \()\)
              A.\( \dfrac {3 \sqrt {10}}{10}\)
              B.\( \dfrac { \sqrt {10}}{10}\)
              C.\( \dfrac {3}{4}\)
              D.\( \dfrac {4}{3}\)
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