优优班--学霸训练营 > 知识点挑题
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            • 1.
              观察下列等式:
              \(① \dfrac {1}{ \sqrt {2}+1}= \dfrac { \sqrt {2}-1}{( \sqrt {2}+1)( \sqrt {2}-1)}= \sqrt {2}-1\);
              \(② \dfrac {1}{ \sqrt {3}+ \sqrt {2}}= \dfrac { \sqrt {3}- \sqrt {2}}{( \sqrt {3}+ \sqrt {2})( \sqrt {3}- \sqrt {2})}= \sqrt {3}- \sqrt {2}\);
              \(③ \dfrac {1}{ \sqrt {4}+ \sqrt {3}}= \dfrac { \sqrt {4}- \sqrt {3}}{( \sqrt {4}+ \sqrt {3})( \sqrt {4}- \sqrt {3})}= \sqrt {4}- \sqrt {3}\);
              \(…\)
              回答下列问题:
              \((1)\)仿照上列等式,写出第\(n\)个等式: ______ ;
              \((2)\)利用你观察到的规律,化简:\( \dfrac {1}{2 \sqrt {3}+ \sqrt {11}}\);
              \((3)\)计算:\( \dfrac {1}{1+ \sqrt {2}}+ \dfrac {1}{ \sqrt {2}+ \sqrt {3}}+ \dfrac {1}{ \sqrt {3}+2}+…+ \dfrac {1}{3+ \sqrt {10}}\).
            • 2.
              你见过像\( \sqrt {4-2 \sqrt {3}}\),\( \sqrt { \sqrt {48}- \sqrt {45}}…\)这样的根式吗?这一类根式叫做复合二次根式\(.\)有一些复合二次根式可以化简,如:\( \sqrt {4-2 \sqrt {3}}= \sqrt {3-2 \sqrt {3}+1}= \sqrt {( \sqrt {3})^{2}-2 \sqrt {3}+1^{2}}= \sqrt {( \sqrt {3}-1)^{2}}= \sqrt {3}-1\),
              请用上述方法化简:\( \sqrt {5-2 \sqrt {6}}\)
            • 3.
              先化简,再求值:\(( \dfrac {2}{a+1}- \dfrac {1}{a})÷ \dfrac {a^{2}b-b}{a^{2}+2a+1}\),其中\(a= \sqrt {2}+1\),\(b= \sqrt {2}-1\).
            • 4.
              先化简,再求值:\( \dfrac {a^{2}-2ab+b^{2}}{2a-2b}÷( \dfrac {1}{b}- \dfrac {1}{a})\),其中\(a= \sqrt {5}+1\),\(b= \sqrt {5}-1\).
            • 5.
              已知\(a\)、\(b\)、\(c\)在数轴上如图,化简\( \sqrt {a^{2}}-|a+b|+ \sqrt {(c-a)^{2}}+|b+c|\).
            • 6.
              已知\(a\),\(b\),\(c\)在数轴上的位置如图所示\(.\)请化简:\( \sqrt {a^{2}}-|a+b|+ \sqrt {(c-a)^{2}}\).
            • 7.
              先化简,再求值:\(a(a+2b)-(a+1)^{2}+2a\),其中\(a= \sqrt {2}+1,b= \sqrt {2}-1\).
            • 8.
              先化简,再求值:\((2x+y)^{2}+(x-y)(x+y)-5x(x-y)\),其中\(x= \sqrt {3}+1\),\(y= \sqrt {3}-1\).
            • 9.
              实践与探索
              \((1)\)填空:\( \sqrt {3^{2}}=\) ______ ;\( \sqrt {(-5)^{2}}=\) ______
              \((2)\)观察第\((1)\)的结果填空:当\(a\geqslant 0\)时\( \sqrt {a^{2}}=\) ______ ;当\(a < 0\)时,\( \sqrt {a^{2}}=\) ______
              \((3)\)利用你总结的规律计算:\( \sqrt {(x-2)^{2}}+ \sqrt {(x-3)^{2}}\),其中\(2 < x < 3\).
            • 10.
              计算:\(2\tan 60^{\circ}- \dfrac {2}{1+ \sqrt {3}}+(2-π)^{0}-( \dfrac {1}{3})^{-1}\).
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