6.
已知,如图,\(\triangle \)\(OBC\)中是直角三角形,\(OB\)与\(x\)轴正半轴重合,\(∠\)\(OBC\)\(=90^{\circ}\),且\(OB\)\(=1\),\(BC\)\(= \sqrt{3} \),将\(\triangle \)\(OBC\)绕原点\(O\)逆时针旋转\(60^{\circ}\)再将其各边扩大为原来的\(m\)倍,使\(OB\)\({\,\!}_{1}=\)\(OC\),得到\(\triangle \)\(OB\)\({\,\!}_{1}\)\(C\)\({\,\!}_{1}\),将\(\triangle \)\(OB\)\({\,\!}_{1}\)\(C\)\({\,\!}_{1}\)绕原点\(O\)逆时针旋转\(60^{\circ}\)再将其各边扩大为原来的\(m\)倍,使\(OB\)\({\,\!}_{2}=\)\(OC\)\({\,\!}_{1}\),得到\(\triangle \)\(OB\)\({\,\!}_{2}\)\(C\)\({\,\!}_{2}\),\(……\),如此继续下去,得到\(\triangle \)\(OB\)\({\,\!}_{2017}\)\(C\)\({\,\!}_{2017}\),则\(m\)\(=\) 。点\(C\)\({\,\!}_{2017}\)的坐标是 。