优优班--学霸训练营 > 知识点挑题
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            • 1.

              已知\(a+b=-2\),\(ab=1\),则化简\(\sqrt{\dfrac{a}{b}}+\sqrt{\dfrac{b}{a}}\)的值为

              A.\(-2\)                 
              B.\({-}\dfrac{1}{2}\)
              C.\(-4\)
              D.\(2\)
            • 2.

              先化简再求值\(\dfrac{2a+2}{a-1}\div \left( a+1 \right)+\dfrac{{{a}^{2}}-1}{{{a}^{2}}-2a+1}\)其中\(a=\sqrt{3}+1\)

            • 3. 化简\( \sqrt{- \dfrac{1}{a}} \)的结果是(    )
              A.\(- \dfrac{ \sqrt{-a}}{a} \)
              B.\(a \sqrt{-a} \)
              C.\(-a \sqrt{-a} \)
              D.\( \dfrac{ \sqrt{-a}}{a} \)
            • 4. 已知a=+1,求代数式a2-2a+3的值.
            • 5.
              观察、思考、解答:
              \(( \sqrt {2}-1)^{2}=( \sqrt {2})^{2}-2×1× \sqrt {2}+1^{2}=2-2 \sqrt {2}+1=3-2 \sqrt {2}\)
              反之\(3-2 \sqrt {2}=2-2 \sqrt {2}+1=( \sqrt {2}-1)^{2}\)
              \(∴3-2 \sqrt {2}=( \sqrt {2}-1)^{2}\)
              \(∴ \sqrt {3-2 \sqrt {2}}= \sqrt {2}-1\)
              \((1)\)仿上例,化简:\( \sqrt {6-2 \sqrt {5}}\);
              \((2)\)若\( \sqrt {a+2 \sqrt {b}}= \sqrt {m}+ \sqrt {n}\),则\(m\)、\(n\)与\(a\)、\(b\)的关系是什么?并说明理由;
              \((3)\)已知\(x= \sqrt {4- \sqrt {12}}\),求\(( \dfrac {1}{x-2}+ \dfrac {1}{x+2})⋅ \dfrac {x^{2}-4}{2(x-1)}\)的值\((\)结果保留根号\()\)
            • 6.
              已知\(x= \sqrt {5}+3\),\(y= \sqrt {5}-3\),求下列各式的值:
              \((1)x^{2}-2xy+y^{2}\)
              \((2)x^{2}-y^{2}\).
            • 7.
              若\(0 < a < 1\),\(a+ \dfrac {1}{a}=6\),则代数式\( \sqrt {a}- \dfrac {1}{ \sqrt {a}}\)的值为\((\)  \()\)
              A.\(±2\)
              B.\(-2\)
              C.\(±4\)
              D.\(4\)
            • 8. 先化简,再求值:\((5x-7+2x^{2})-(x^{2}+2x)-(x-5)\),其中\(x= \sqrt {2}-1\).
            • 9. 根据题目条件,求代数式的值:
              \((1)\)已知\( \dfrac {1}{x}- \dfrac {1}{y}=3\),求\( \dfrac {5x+xy-5y}{x-xy-y}\)的值;
              \((2)\)若\(x= \dfrac { \sqrt {11}+ \sqrt {7}}{2}\),\(y= \dfrac { \sqrt {11}- \sqrt {7}}{2}\),求代数式\(x^{2}-xy+y^{2}\)的值.
            • 10.
              已知\(a-b=2+ \sqrt {3}\),\(b-c=2- \sqrt {3}\),则\(a^{2}+b^{2}+c^{2}-ab-bc-ac\)的值为\((\)  \()\)
              A.\(10 \sqrt {3}\)
              B.\(12 \sqrt {3}\)
              C.\(10\)
              D.\(15\)
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