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            • 1.
              如图,在边长为\(a\)正方形\(ABCD\)中,把边\(BC\)绕点\(B\)逆时针旋转\(60^{\circ}\),得到线段\(BM\),连接\(AM\)并延长交\(CD\)于\(N\),连接\(MC\),则\(\triangle MNC\)的面积为\((\)  \()\)
              A.\( \dfrac { \sqrt {3}-1}{2}a^{2}\)
              B.\( \dfrac { \sqrt {2}-1}{2}a^{2}\)
              C.\( \dfrac { \sqrt {3}-1}{4}a^{2}\)
              D.\( \dfrac { \sqrt {2}-1}{4}a^{2}\)
            • 2.
              如图,在\(\triangle ABC\)中,\(∠C=90^{\circ}\),\(AC=3\),\(BC=4\),点\(O\)是\(BC\)中点,将\(\triangle ABC\)绕点\(O\)旋转得\(\triangle A′B{{'}}C\),则在旋转过程中点\(A\)、\(C′\)两点间的最大距离是 ______ .
            • 3.
              将矩形\(ABCD\)绕点\(A\)顺时针旋转\(α(0^{\circ} < α < 360^{\circ})\),得到矩形\(AEFG\).

              \((1)\)如图,当点\(E\)在\(BD\)上时\(.\)求证:\(FD=CD\);
              \((2)\)当\(α\)为何值时,\(GC=GB\)?画出图形,并说明理由.
            • 4.
              如图,在\(\triangle ABC\)中,\(∠ACB=90^{\circ}\),\(AC=BC\),\(D\)是\(AB\)边上一点\((\)点\(D\)与\(A\),\(B\)不重合\()\),连结\(CD\),将线段\(CD\)绕点\(C\)按逆时针方向旋转\(90^{\circ}\)得到线段\(CE\),连结\(DE\)交\(BC\)于点\(F\),连接\(BE\).
              \((1)\)求证:\(\triangle ACD\)≌\(\triangle BCE\);
              \((2)\)当\(AD=BF\)时,求\(∠BEF\)的度数.
            • 5.
              如图,等边三角形\(ABC\)的边长为\(4\),点\(O\)是\(\triangle ABC\)的中心,\(∠FOG=120^{\circ}\),绕点\(O\)旋转\(∠FOG\),分别交线段\(AB\)、\(BC\)于\(D\)、\(E\)两点,连接\(DE\),给出下列四个结论:\(①OD=OE\);\(②S_{\triangle ODE}=S_{\triangle BDE}\);\(③\)四边形\(ODBE\)的面积始终等于\( \dfrac {4}{3} \sqrt {3}\);\(④\triangle BDE\)周长的最小值为\(6.\)上述结论中正确的个数是\((\)  \()\)
              A.\(1\)
              B.\(2\)
              C.\(3\)
              D.\(4\)
            • 6.
              如图,点\(E\)是正方形\(ABCD\)的边\(DC\)上一点,把\(\triangle ADE\)绕点\(A\)顺时针旋转\(90^{\circ}\)到\(\triangle ABF\)的位置,若四边形\(AECF\)的面积为\(25\),\(DE=2\),则\(AE\)的长为\((\)  \()\)
              A.\(5\)
              B.\( \sqrt {23}\)
              C.\(7\)
              D.\( \sqrt {29}\)
            • 7.
              如图,在矩形\(ABCD\)中,\(AB=5\),\(BC=4\),以\(CD\)为直径作\(⊙O.\)将矩形\(ABCD\)绕点\(C\)
              旋转,使所得矩形\(A′B′C′D′\)的边\(A′B′\)与\(⊙O\)相切,切点为\(E\),边\(CD′\)与\(⊙O\)相交于点
              \(F\),则\(CF\)的长为 ______ .
            • 8.
              如图,\(C\)为半圆内一点,\(O\)为圆心,直径\(AB\)长为\(2cm\),\(∠BOC=60^{\circ}\),\(∠BCO=90^{\circ}\),将\(\triangle BOC\)绕圆心\(O\)逆时针旋转至\(\triangle B′OC′\),点\(C′\)在\(OA\)上,则边\(BC\)扫过区域\((\)图中阴影部分\()\)的面积为 ______ \(cm^{2}\).
            • 9.
              如图,矩形\(ABCD\)中,\(AC=2AB\),将矩形\(ABCD\)绕点\(A\)旋转得到矩形\(AB′C′D′\),使点\(B\)的对应点\(B{{'}}\)落在\(AC\)上,\(B{{'}}C{{'}}\)交\(AD\)于点\(E\),在\(B{{'}}C′\)上取点\(F\),使\(B{{'}}F=AB\).
              \((1)\)求证:\(AE=C′E\).
              \((2)\)求\(∠FBB{{'}}\)的度数.
              \((3)\)已知\(AB=2\),求\(BF\)的长.
            • 10. 如图四边形ABCD是菱形,且∠ABC=60,△ABE是等边三角形,M为对角线BD(不含B点)上任意一点,将BM绕点B逆时针旋转60°得到BN,连接EN、AM、CM,则下列五个结论中正确的是(  )
              ①若菱形ABCD的边长为1,则AM+CM的最小值1;
              ②△AMB≌△ENB;
              ③S四边形AMBE=S四边形ADCM
              ④连接AN,则AN⊥BE;
              ⑤当AM+BM+CM的最小值为2 时,菱形ABCD的边长为2.
              A.①②③
              B.②④⑤
              C.①②⑤
              D.②③⑤
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