优优班--学霸训练营 > 知识点挑题
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            • 1. 先化简,再求值
              [(
              2
              xy+1)(
              2
              xy-1)-(xy+1)2+3]÷(1-xy),其中x=10,y=5-1
            • 2. 计算或化简:
              (1)-22+(-
              1
              2
              -2-(π-5)0-|-4|;
              (2)(-a32+a2•a4-(2a42÷a2
            • 3. 计算:
              (1)-22+30-(-
              1
              2
              -1           
              (2)2m3m2-(2m42÷m3
              (3)(2x+3y)2(2x-3y)2        
              (4)(2a+b)(b-2a)-(a-3b)2
            • 4. 已知n为正整数,且x2n=4,求(x3n2-2(x22n的值.
            • 5. (1)(-a)2•(a22÷a3;                       
              (2)-4a(2a2+3a-1)
              (3)(-1)2006+(-
              1
              2
              -2-(3.14-π)0+(-2)3       
              (4)(2x-3y)2-(y+3x)(3x-y)
              (5)(2x-y+1)(2x+y-1)
              (6)用简便方法计算:1232-121×119
              (7)先化简,再求值:(2x+3)(2x-3)-2x(x-1)-2(x-1)2,其中x=-1.
            • 6. 计算:
              (1)2x3y•(-3xy)2÷
              1
              2
              xy2
              (2)(-1)2016+(-
              1
              2
              -4-(3.14-π)0
              (3)(2x)2-(-2x+3)(-2x-3)
              (4)20162-2013×2019.
            • 7. 计算:
              (1)(π-3.14)0+2-2+(-3)2-(
              1
              2
              )-2

              (2)(-2xy2)3•(-3x2y3)2•(
              1
              4
              xy)

              (3)a2•a3•a5+(-2a52-a12÷a2
              (4)(2x+1)(2x-1)-4(x-1)2
            • 8. 计算:
              (1)(2x3y)2•(-2xy)+(-2x3y)3÷(2x2
              (2)(6m2n-6m2n2-3m2)÷(-3m2
              (3)先化简,再求值:2(x+1)2-5(x+1)(x-1)+3(x-1)2,其中x=(
              1
              2
              -1
            • 9. (1)(-4x2y3)•(-
              1
              8
              xyz)÷(
              1
              2
              xy22 
              (2)(54x2y-108xy2-36xy)÷(18xy) 
              (3)(a+b+3)(a+b-3)
              (4)20070+2-2-(
              1
              2
              2+2014.
            • 10. (1)(2a+1)2-(2a+1)(-1+2a)
              (2)
              1
              2
              a2bc3•(-2a2b2c)2
              (3)(2x-y)(4x2-y2)(2x+y)
              (4)(54x2y-108xy2-36xy)÷18xy
              (5)(2x+3y)(2x-3y)-(2x+3y)2
            0/40

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