优优班--学霸训练营 > 知识点挑题
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            • 1.

              计算:

                  \((1)(-3x)·(2x^{2}-x-1)\);

                  \((2)\left( -\dfrac{1}{2}x \right)\cdot (4{{x}^{2}}+2x-1)-\dfrac{1}{3}{{x}^{2}}(3x-6{{x}^{2}})\).

            • 2. 计算:
              \((1){{\left( -{{x}^{4}} \right)}^{3}}\div {{\left( -{{x}^{3}} \right)}^{2}}\cdot \left[ {{\left( -x \right)}^{3}}\div {{\left( -x \right)}^{2}} \right]\)

              \((2)\)\((7+4\sqrt{3}){{(2-\sqrt{3})}^{2}}+(2+\sqrt{3})(2-\sqrt{3});\)

            • 3.

              先化简,再求值:\((3x+2)(3x-2)-5x(x+1)-{{(x-1)}^{2}}\),其中\(x^{2}-x-2018=0\).

            • 4.

              \((1)a(a^{2}-3)+a^{2}(a+3)-3a(a^{2}-a-1)\)

              \((2)(x-6)(x+4)-3(x+5)(x-8)\)

            • 5.
              化简求值:\([(x+2y)^{2}-(x+y)(3x-y)-5y^{2}]÷2x\),其中\(x=-2\),\(y= \dfrac {1}{2}\).
            • 6. 先化简,再求值:\((2a+b)(2a-b)+(4ab^{3}-8ab^{2})÷(4ab)\),其中\(a=2\),\(b=1\).
            • 7.

              \((1)\)已知一个多项式除以\(2x^{2}y\),其商为\(4{{x}^{3}}{{y}^{2}}-6{{x}^{3}}y+2{{x}^{4}}{{y}^{2}}\),求原多项式;

                  \((2)\)已知被除式为\(15xy-10xy^{2}\),商为\(-4xy\),余式为\(3xy-2xy^{2}\),求除式.

            • 8.
              计算:
              \((1) \sqrt{4}-2×{\left( \dfrac{1}{2}\right)}^{-1}+\left|-3\right|+{\left( \sqrt{2}-1\right)}^{0} \)    

              \((2)(-x)⋅(3xy-6x^{2}y^{2})÷(3x^{2})\)

            • 9.

              计算:

              \((1){{\left( -{{a}^{2}} \right)}^{3}}-6{{a}^{2}}\bullet {{a}^{4}}\)                          \((2){\left(p-q\right)}^{4}÷{\left(q-p\right)}^{3}·{\left(p-q\right)}^{2} \)




              \((3){{(3.14-\pi )}^{0}}-{{3}^{2}}+\left| -4 \right|+{{(\dfrac{1}{2})}^{-1}}\)              \((4)(x+1)({{x}^{2}}-2x-3)\)  







              \((5)(2a+b)(b-2a)-(a-3b)^{2}\)                     \((6)\)  \({{(x+1)}^{2}}{{(x-1)}^{2}}\)

            • 10.

              计算:

              \((1){{(-\dfrac{n}{m})}^{-3}}\);

              \((2)(3x^{2}y^{-2})^{-3}\);

              \((3)\dfrac{3{{x}^{-2}}{{y}^{-3}}}{4{{x}^{-5}}{{y}^{2}}}\);

              \((4)5a^{-5}b^{2}-(2ab^{-1})^{2}\);

              \((5)(m^{3}n)^{-2}·(2m^{-2}n^{-3})^{-2}\).

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