阅读下面材料,解答后面的问题
解方程:\(\dfrac{x-1}{x}- \dfrac{4x}{x-1}=0 \).
解:设\(y= \dfrac{x-1}{x} \),则原方程化为:\(y- \dfrac{4}{y}=0 \),方程两边同时乘\(y\)得:\(y^{2}-4=0\),
解得:\(y=±2\),
经检验:\(y=±2\)都是方程\(y- \dfrac{4}{y}=0 \)的解,\(∴\)当\(y=2\)时,\(\dfrac{x-1}{x}=2 \),解得:\(x=-1\),
当\(y=-2\)时,\(\dfrac{x-1}{x}=-2 \),解得:\(x=\dfrac{1}{3} \),经检验:\(x=-1\)或\(x=\dfrac{1}{3} \)都是原分式方程的解,
\(∴\)原分式方程的解为\(x=-1\)或 \(x=\dfrac{1}{3} .\)上述这种解分式方程的方法称为换元法.
问题:\((1)\)若在方程\(\dfrac{x-1}{4x}- \dfrac{x}{x-1}=0 \)中,设\(y= \dfrac{x-1}{x} \),则原方程可化为:_____;
\((2)\)若在方程\(\dfrac{x-1}{x+1}- \dfrac{4x+4}{x-1}=0 \)中,设\(y= \dfrac{x-1}{x} \),则原方程可化为:_____;
\((3)\)模仿上述换元法解方程:\(\dfrac{x-1}{x+2}- \dfrac{3}{x-1}-1=0 \).