如图,在\(\triangle ABC\)中,\(∠ABC\)和\(∠ACB\)的平分线相交于点\(G\),过点\(G\)作\(EF/\!/BC\)交\(AB\)于\(E\),交\(AC\)于\(F\),过点\(G\)作\(GD⊥AC\)于\(D\),下列四个结论:
\(①EF=BE+CF\);
\(②∠BGC=90^{\circ}+ \dfrac {1}{2}∠A\);
\(③\)点\(G\)到\(\triangle ABC\)各边的距离相等;
\(④\)设\(GD=m\),\(AE+AF=n\),则\(S_{\triangle AEF}=mn\).
其中正确的结论是 ______ .