如图,点\(O\)是等边\(\triangle ABC\)内一点,\(∠AOB=110^{\circ}\),\(∠BOC=α\),将\(\triangle BOC\)绕点\(C\)顺时针方向旋转\(60^{\circ}\),到\(\triangle ADC\),连接\(OD\).
\((1)\)求证:\(\triangle COD\)是等边三角形;
\((2)\)当\(α=150^{\circ}\)时,试判断\(\triangle AOD\)的形状,并说明理由.
\((3)\)探索:当\(α\)为多少度时,\(\triangle AOD\)是等腰三角形.