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            • 1.
              \((1)\)已知\(\log _{2}(16-2^{x})=x\),求\(x\)的值
              \((2)\)计算:\((- \dfrac {1}{ \sqrt {5}- \sqrt {3}})^{0}+81^{0.75}- \sqrt {(-3)^{2}}×8^{ \frac {2}{3}}+\log _{5}7⋅\log _{7}25\).
            • 2.
              有下列各式:
              \(① \sqrt[n]{a^{n}}=a\);
              \(②\)若\(a∈R\),则\((a^{2}-a+1)^{0}=1\);
              \(③ \sqrt[3]{x^{4}+y^{3}}=x^{ \frac {4}{3}}+y\);
              \(④ \sqrt[3]{5}= \sqrt[6]{(-5)^{2}}\).
              其中正确的个数是\((\)  \()\)
              A.\(0\)
              B.\(1\)
              C.\(2\)
              D.\(3\)
            • 3.

              已知\(2^{x}=3\),\({\log }_{2} \dfrac{4}{3}=y \),则\(x+y\)的值等于________.

            • 4.
              在由正数组成的等比数列\(\{a_{n}\}\)中,若\(a_{3}a_{4}a_{5}=3^{π}\),则\(\sin (\log _{3}a_{1}+\log _{3}a_{2}+…+\log _{3}a_{7})\)的值为\((\)   \()\)
              A.\(\dfrac{1}{2}\)
              B.\(\dfrac{\sqrt{3}}{2}\)
              C.\(1\)
              D.\(-\dfrac{\sqrt{3}}{2}\)
            • 5.
              求值:
              \((I)(2 \dfrac {1}{4})^{ \frac {1}{2}}-(-9.6)^{0}-(3 \dfrac {3}{8})^{- \frac {2}{3}}+(1.5)^{-2}\);
              \((II)\) \(\lg 14-2\lg \dfrac {7}{3}+\lg 7-\lg 18\).
            • 6.
              计算:\(e^{\ln 3}+\log _{ \sqrt {3}}9+(0.125)^{- \frac {2}{3}}=\) ______ .
            • 7.

              求值\((\)Ⅰ\()(3 \dfrac{3}{8}{)}^{ \frac{2}{3}}(5 \dfrac{4}{9}{)}^{0.5}+[(-2{)}^{3}{]}^{- \frac{4}{3}}÷0.{0625}^{0.25}-(-π{)}^{0} \)

              \((\)Ⅱ\(){2}^{{\log }_{2} \frac{1}{4}}+( \sqrt{2}-1{)}^{\ln 1}+ \dfrac{1}{1+{\log }_{2}3}-{\log }_{36} \dfrac{1}{9} \)

            • 8.

              若\(x\in \left( {{e}^{-1}},1 \right)\),\(a=\ln x\),\(b=( \dfrac{1}{2} )^{\ln x}\),\(c=e^{\ln x}\),则\(a\),\(b\),\(c\)的大小关系为

              A.\(c > b > a\)      
              B.\(b > c > a\)    
              C.\(a > b > c\)    
              D.\(b > a > c\)
            • 9.

              已知函数\(f(x)=\begin{cases} & {{\log }_{\frac{1}{2}}}x,x > 1 \\ & \dfrac{1}{{{2}^{x-1}}},x\leqslant 1 \end{cases}\),则\(f(f(4)) =\)(    )


              A.\(-3\)  
              B.\(\dfrac{1}{8}\)
              C.\(3\)
              D.\(8\)
            • 10.

              计算:\({3}\sqrt{{12}}\div {3}\sqrt{\dfrac{{1}}{{3}}}{-2}\sqrt{{3}}{-}\left| \sqrt[{3}]{{8}}{-4} \right|{-}{{\left( \dfrac{{1}}{{2}} \right)}^{{-2}}}\)结果为\((\)    \()\)

              A.\(-2\sqrt{3}\)
              B.\(\sqrt{3}\)
              C.\(6-2\sqrt{3}\)
              D.\(36-2\sqrt{3}\)
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