观察以下\(3\)个等式:
\(\dfrac{1}{1\times 3}=\dfrac{1}{2\times 1+1}\) ,
\(\dfrac{1}{1\times 3}+\dfrac{1}{3\times 5}=\dfrac{2}{2\times 2+1}\),
\(\dfrac{1}{1\times 3}+\dfrac{1}{3\times 5}+\dfrac{1}{5\times 7}=\dfrac{3}{2\times 3+1}\),
\(\cdots \cdots \cdots \cdots \cdots \)
\((1)\)照以上式子规律,猜想第\(n\)个等式\((n∈N^{*})\);
\((2)\)用数学归纳法证明上述所猜想的第\(n\)个等式成立\((n∈N^{*}).\)