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            • 1.
              已知椭圆\(C\):\( \dfrac {x^{2}}{a^{2}}+ \dfrac {y^{2}}{b^{2}}=1(a > b > 0)\)的长轴长为\(4\),焦距为\(2 \sqrt {2}\).
              \((\)Ⅰ\()\)求椭圆\(C\)的方程;
              \((\)Ⅱ\()\)过动点\(M(0,m)(m > 0)\)的直线交\(x\)轴于点\(N\),交\(C\)于点\(A\),\(P(P\)在第一象限\()\),且\(M\)是线段\(PN\)的中点,过点\(P\)作\(x\)轴的垂线交\(C\)于另一点\(Q\),延长\(QM\)交\(C\)于点\(B\).
              \((ⅰ)\)设直线\(PM\),\(QM\)的斜率分别为\(k\),\(k′\),证明\( \dfrac {k′}{k}\)为定值;
              \((ⅱ)\)求直线\(AB\)的斜率的最小值.
            • 2.
              I. 在平面直角坐标系\(xOy\)中,直线\(l\)过点\(P(1,2)\),且倾斜角为\(α\),\(α ∈\)\(\left.\begin{matrix} \\ \end{matrix}\right( \)\(0\),\( \dfrac{π}{2}\left)\begin{matrix} \\ \end{matrix}\right.\) \(.\)以直角坐标系的原 点\(O\)为极点,\(x\)轴的非负半轴为极轴建立极坐标系,曲线\(C\)的极坐标方程为\(ρ\)\({\,\!}^{2}\) \((3 + \sin \)\({\,\!}^{2}\) \(θ)= 12\).
              \((1)\)求直线\(l\)的参数方程和曲线\(C\)的直角坐标方程,并判断曲线\(C\)是什么曲线;

              \((2)\)设直线\(l\)与曲线\(C\)相交于\(M\)、\(N\)两点,当\(|PM|·|PN|= 2\)时,求\(α\)的值.



              \(II\).已知已知函数\(ƒ(x)=|x − 2a|+|x + 3|\),\(g(x)=|x − 2|+ 3\).
              \((1)\)解不等式\(|g(x)| < 6\);

              \((2)\)若对任意的\(x\)\({\,\!}_{2}\) \(∈ R\),均存在\(x\)\({\,\!}_{1}\) \(∈ R\),使得\(g(x\)\({\,\!}_{1}\)\()= ƒ(x\)\({\,\!}_{2}\)\()\)成立,求实数\(a\)的取值范围.

            • 3.

              已知圆\({{F}_{1}}\):\({{\left( x+2 \right)}^{2}}+{{y}^{2}}=36\),定点\({{F}_{2}}\left( 2,0 \right)\),\(A\)是圆\({{F}_{1}}\)上的一动点,线段\({{F}_{2}}A\) 的垂直平分线交半径\({{F}_{1}}A\)\(P\)点,则\(P\)点的轨迹\(C\)的方程是\((\)   \()\)

              A.\(\dfrac{{{x}^{2}}}{4}+\dfrac{{{y}^{2}}}{3}=1\)
              B.\(\dfrac{{{x}^{2}}}{9}+\dfrac{{{y}^{2}}}{5}=1\)
              C.\(\dfrac{{{x}^{2}}}{3}+\dfrac{{{y}^{2}}}{4}=1\)
              D.\(\dfrac{{{x}^{2}}}{5}+\dfrac{{{y}^{2}}}{9}=1\)
            • 4.
              在平面直角坐标系 \(xOy\)中,已知椭圆 \(C\)\({\,\!}_{1}\):\( \dfrac{x^2 }{a^2 }+ \dfrac{y^2 }{b^2 }=1( \)\(a\)\( > \) \(b\)\( > 0)\)的左焦点为 \(F\)\({\,\!}_{1}(-1,0)\),且点 \(P\)\((0,1)\)在 \(C\)\({\,\!}_{1}\)上\(.\)

              \((1)\)求椭圆\(C\)\({\,\!}_{1}\)的方程;

              \((2)\)设直线\(l\)同时与椭圆\(C\)\({\,\!}_{1}\)和抛物线\(C\)\({\,\!}_{2}\):\(y\)\({\,\!}^{2}=4\)\(x\)相切,求直线\(l\)的方程.

            • 5.

              已知椭圆\( \dfrac{x^{2}}{25}+ \dfrac{y^{2}}{m^{2}}=1(\)\(m\)\( > 0)\)的左焦点为\(F\)\({\,\!}_{1}(-4,0)\),则\(m\)\(=(\)  \()\)

              A.\(2\)        
              B.\(3\)        
              C.\(4\)            
              D.\(9\)
            • 6.
              已知直线\(x-2y+4=0\)经过椭圆\( \dfrac {x^{2}}{a^{2}}+ \dfrac {y^{2}}{b^{2}}=1(a > b > 0)\)的顶点和焦点,则椭圆的标准方程为\((\)  \()\)
              A.\( \dfrac {x^{2}}{20}+ \dfrac {y^{2}}{16}=1\)
              B.\( \dfrac {x^{2}}{20}+ \dfrac {y^{2}}{4}=1\)
              C.\( \dfrac {x^{2}}{16}+ \dfrac {y^{2}}{12}=1\)
              D.\( \dfrac {x^{2}}{16}+ \dfrac {y^{2}}{4}=1\)
            • 7.

              设\({F}_{1},{F}_{2} \)分别是椭圆\(E:{{x}^{2}}+\dfrac{{{y}^{2}}}{{{b}^{2}}}=1(0 < b < 1)\)的左、右焦点,已知过点\({{F}_{1}}\) 的直线交椭圆\(E\)于 \(A\),\(B\)两点,若\(\left| A{{F}_{1}} \right|=2\left| B{{F}_{1}} \right|\),\(A{{F}_{2}}\bot x\)轴,则椭圆\(E\)的方程为   \((\)  \()\)

              A.\({{x}^{2}}+\dfrac{3{{y}^{2}}}{2}=1\)
              B.\({{x}^{2}}+\dfrac{6{{y}^{2}}}{5}=1\)
              C.\({{x}^{2}}+\dfrac{5{{y}^{2}}}{4}=1\)
              D.\({{x}^{2}}+\dfrac{8{{y}^{2}}}{7}=1\)
            • 8.

              “方程\(m{{x}^{2}}+n{{y}^{2}}=1\)表示焦点在\(y\)轴上的椭圆”是“\(m > n\)”的\((\)  \()\)



              A.充分而不必要条件   
              B.必要而不充分条件  
              C.充要条件            
              D.既不充分也不必要条件
            • 9.
              在\(\triangle ABC\)中,已知\(A(-1,0)\),\(C(1,0)\),且\(|BC|\),\(|CA|\),\(|AB|\)成等差数列,则顶点\(B\)的轨迹方程是\((\)  \()\)
              A.\( \dfrac {x^{2}}{3}+ \dfrac {y^{2}}{4}=1\)
              B.\( \dfrac {x^{2}}{3}+ \dfrac {y^{2}}{4}=1(x\neq ± \sqrt {3})\)
              C.\( \dfrac {x^{2}}{4}+ \dfrac {y^{2}}{3}=1\)
              D.\( \dfrac {x^{2}}{4}+ \dfrac {y^{2}}{3}=1(x\neq ±2)\)
            • 10. 与\( \sqrt {(x+3)^{2}+y^{2}}+ \sqrt {(x-3)^{2}+y^{2}}=10\)等价的方程是\((\)  \()\)
              A.\( \dfrac {x^{2}}{25}+ \dfrac {y^{2}}{9}=1\)
              B.\( \dfrac {y^{2}}{25}+ \dfrac {x^{2}}{9}=1\)
              C.\( \dfrac {x^{2}}{25}+ \dfrac {y^{2}}{16}=1\)
              D.\( \dfrac {y^{2}}{25}+ \dfrac {x^{2}}{16}=1\)
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