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            • 1.

              选修\(4-1:\)几何证明选讲

              如图,\(AB\)为半圆\(O\)的直径,直线\(PC\)切半圆\(O\)于点\(C\),\(AP⊥PC\),\(P\)为垂足.


              \((1)\) 求证:\(∠PAC=∠CAB;\)

              \((2)\) 求证:\(AC^{2}=AP·AB.\) 

            • 2.

              如图,点列\(\{A_{n}\}\),\(\{B_{n}\}\)分别在某锐角的两边上,且\(\left| {{A}_{n}}{{A}_{n+1}} \right|=\left| {{A}_{n+1}}{{A}_{n+2}} \right|,{{A}_{n}}\ne {{A}_{n+2}},n\in {{N}^{*}}\),\(\left| {{B}_{n}}{{B}_{n+1}} \right|=\left| {{B}_{n+1}}{{B}_{n+2}} \right|,{{B}_{n}}\ne {{B}_{n+2}},n\in {{N}^{*}}\),\((P\neq Q \)表示点\(P\)与\(Q\)不重合\()\),若\({d}_{n}=\left|{A}_{n}{B}_{n}\right| \) \(S_{n}\)为\(∆{A}_{n}{B}_{n}{B}_{n+1} \)的面积,则\((\)     \()\)


              A.\({ }\!\!\{\!\!{ }S_{n}^{{}}{ }\!\!\}\!\!{ }\)是等差数列     
              B.\({ }\!\!\{\!\!{ }S_{n}^{2}{ }\!\!\}\!\!{ }\)是等差数列
              C.\({ }\!\!\{\!\!{ }d_{n}^{{}}{ }\!\!\}\!\!{ }\)是等差数列     
              D.\({ }\!\!\{\!\!{ }d_{n}^{2}{ }\!\!\}\!\!{ }\)是等差数列
            • 3. 已知在梯形\(ABCD\)中\((\)如图\()\),\(AB=DC=DA\),\(AC\)和\(BD\)是梯形的对角线\(.\)求证:\(CA\)平分\(∠BCD\),\(BD\)平分\(∠CBA\).

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