优优班--学霸训练营 > 知识点挑题
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            • 1. 已知数列\(\{a_{n}\}\)的通项公式为\(a_{n}=2^{5-n}\),数列\(\{b_{n}\}\)的通项公式为\(b_{n}=n+k\),设\(c_{n}= \begin{cases} \overset{b_{n},a_{n}\leqslant b_{n}}{a_{n},a_{n} > b_{n}}\end{cases}\)若在数列\(\{c_{n}\}\)中,\(c_{5}\leqslant c_{n}\)对任意\(n∈N^{*}\)恒成立,则实数\(k\)的取值范围是______.
            • 2.
              已知函数\(f(x)\),给出如下定义:若\(f_{1}(x)\),\(f_{2}(x)\),\(…\),\(f_{n}(x)\),\(…\)均为定义在同一个数集下的函数,且\(f_{1}(x)=f(x)\),\(f_{n}(x)=f(f_{n-1}(x))\),其中\(n=2\),\(3\),\(4\),\(…\),则称\(f_{1}(x)\),\(f_{2}(x)\),\(…\),\(f_{n}(x)\),\(…\)为一个嵌套函数列,记为\(\{f_{n}(x)\}\),若存在非零实数\(λ\),使得嵌套函数列\(\{f_{n}(x)\}\)满足\(f_{n-1}(x)=λf_{n}(x)\),则称\(\{f_{n}(x)\}\)为类等比函数列.
              \((\)Ⅰ\()\)已知\(\{f_{n}(x)\}\)是定义在\(R\)上的嵌套函数列,若\(f(x)= \dfrac {x}{2}+ \dfrac {1}{4}\).
              \(①\)求\(f(2)\),\(f_{2}(2)\),\(f_{3}(2)\).
              \(②\)证\(\{f_{n}(x)- \dfrac {1}{2}\}\)是类等比函数列.
              \((\)Ⅱ\()\)已知\(\{g_{n}(x)\}\)是定义在\((1,+∞)\)上嵌套函数列.
              若\(g(x)= \dfrac {1}{2}(x+ \dfrac {1}{x})\),求证\(|g_{n+1}(x)-g_{n}(x)| < \dfrac {1}{2^{n}}|x- \dfrac {1}{x}|.\)
            • 3. 已知数列\(\{a_{n}\}\)是首项为\(a_{1}= \dfrac {1}{4}\),公比\(q= \dfrac {1}{4}\)的等比数列,设\(b_{n}+2=3\log \;_{ \frac {1}{4}}a_{n}(n∈N^{*})\),数列\(\{c_{n}\}\)满足\(c_{n}=a_{n}⋅b_{n}.(\)Ⅰ\()\)求数列\(\{c_{n}\}\)的前\(n\)项和\(S_{n}\);
              \((\)Ⅱ\()\)若\(c_{n}\leqslant \dfrac {1}{4}m^{2}+m-1\)对一切正整数\(n\)恒成立,求实数\(m\)的取值范围.
            • 4.
              设函数\(f(x)=2x-\cos 4x\),\(\{a_{n}\}\)是公差为\( \dfrac {π}{8}\)的等差数列,\(f(a_{1})+f(a_{2})+…+f(a_{8})=11π\),则\([f(a_{2})]^{2}-a_{1}a_{5}=(\)  \()\)
              A.\(0\)
              B.\( \dfrac {1}{8}π^{2}\)
              C.\( \dfrac {3}{8}π^{2}\)
              D.\( \dfrac {13}{16}π^{2}\)
            • 5.
              已知数列\(\{a_{n}\}\)的前\(n\)项和为\(S_{n}\),对一切正整数\(n\),点\(P_{n}(n,S_{n})\)都在函数\(f(x)=x^{2}+2x\)的图象上,记\(a_{n}\)与\(a_{n+1}\)的等差中项为\(k_{n}\).
              \((\)Ⅰ\()\)求数列\(\{a_{n}\}\)的通项公式;
              \((\)Ⅱ\()\)若\(b_{n}=2^{k_{n}}\cdot a_{n}\),求数列\(\{b_{n}\}\)的前\(n\)项和\(T_{n}\);
              \((\)Ⅲ\()\)设集合\(A=\{x|x=k_{n},n∈N^{*}\},B=\{x|x=2a_{n},n∈N^{*}\}\),等差数列\(\{c_{n}\}\)的任意一项\(c_{n}∈A∩B\),其中\(c_{1}\)是\(A∩B\)中的最小数,且\(110 < c_{10} < 115\),求\(\{c_{n}\}\)的通项公式.
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