共50条信息
\((1)\dfrac{{2}+{2i}}{{{({1}-{i})}^{{2}}}}+{{\left( \dfrac{\sqrt{{2}}}{{1}+{i}} \right)}^{{2016}}}\)；
\((2)i+i^{2}+…+i^{2017}\)．
\((1)\dfrac{{2}+{2i}}{{{({1}-{i})}^{{2}}}}+{{\left( \dfrac{\sqrt{{2}}}{{1}+{i}} \right)}^{{2010}}}\)；
\((2)(4-i^{5})(6+2i^{7})+(7+i^{11})(4-3i)\)．
复数\({{\left( \dfrac{1-i}{1+i} \right)}^{10}}\)的值是____________．
计算：\((1)\) \((4-{{i}^{5}})(6+2{{i}^{7}})+(7+{{i}^{11}})(4-3i)\) \((2)\) \(\dfrac{5{{(4+i)}^{2}}}{i(2+i)}\)
已知\(i\)是虚数单位，复数\(z=(1+i)·i^{3}\)，则 \(\dfrac{1}{z}\) 的共轭复数是( )
设 \(f\left(n\right)={i}^{n}+{i}^{-n}\left(n∈N\right) \) ，则集合\(\left\{x \left|x=f\left(n\right) \right.\right\} \)中元素的个数为
已知复数\(f(n)={{i}^{n}}(n\in N*)\)，则集合\(\left\{ z|z=f(n) \right\}\)中元素的个数是\((\) \()\)
已知\(i\)是虚数单位，则\(1+\)\(i\)\(+\)\(i\)\({\,\!}^{2}…+\)\(i\)\({\,\!}^{2018}\)等于( )
进入组卷