已知正方体\(ABCD-A_{1}B_{1}C_{1}D_{1}\),点\(E\),\(F\),\(G\)分别是线段\(B_{1}B\),\(AB\)和\(A_{1}C\)上的动点,观察直线\(CE\)与\(D_{1}F\),\(CE\)与\(D_{1}\)G.给出下列结论:
\(①\)对于任意给定的点\(E\),存在点\(F\),使得\(D_{1}F⊥CE\);
\(②\)对于任意给定的点\(F\),存在点\(E\),使得\(CE⊥D_{1}F\);
\(③\)对于任意给定的点\(E\),存在点\(G\),使得\(D_{1}G⊥CE\);
\(④\)对于任意给定的点\(G\),存在点\(E\),使得\(CE⊥D_{1}\)G.
其中正确结论的序号是\((\) \()\)